A 6 MHz channel is used by a digital signalling system initializing fo...
Explanation:
Bandwidth of the channel = 6 MHz
Number of levels used for signalling = 4
Maximum possible transmission rate:
The maximum possible transmission rate for a digital signalling system can be calculated using Nyquist formula:
Maximum possible transmission rate = 2 x bandwidth x log2 (number of levels)
= 2 x 6 x 10^6 x log2(4)
= 6 x 10^6 bits/s
Therefore, the maximum possible transmission rate is 6 M bits/s.
However, the question asks for the maximum possible transmission rate in bands per second.
Since the bandwidth of the channel is 6 MHz, the maximum possible transmission rate in bands per second is:
Maximum possible transmission rate = bandwidth
= 6 MHz
Therefore, the maximum possible transmission rate in bands per second is 6M bands/s.
Final answer: Option A.
A 6 MHz channel is used by a digital signalling system initializing fo...
D