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A 6 MHz channel is used by a digital signalling system initializing four-level signals. The maximum possible transmission rate is
  • a)
    6M bands/s
  • b)
    12M bands/s
  • c)
    6 M bits/s
  • d)
    12M bits/s
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A 6 MHz channel is used by a digital signalling system initializing fo...
Explanation:

Bandwidth of the channel = 6 MHz

Number of levels used for signalling = 4

Maximum possible transmission rate:

The maximum possible transmission rate for a digital signalling system can be calculated using Nyquist formula:

Maximum possible transmission rate = 2 x bandwidth x log2 (number of levels)

= 2 x 6 x 10^6 x log2(4)

= 6 x 10^6 bits/s

Therefore, the maximum possible transmission rate is 6 M bits/s.

However, the question asks for the maximum possible transmission rate in bands per second.

Since the bandwidth of the channel is 6 MHz, the maximum possible transmission rate in bands per second is:

Maximum possible transmission rate = bandwidth

= 6 MHz

Therefore, the maximum possible transmission rate in bands per second is 6M bands/s.

Final answer: Option A.
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