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If the magnetic bearing of the sun at a place at noon in southern hemisphere is 167º, the magnetic declination at that place is
- a)77º N
- b)23º S
- c)13º E
- d)13º W
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
If the magnetic bearing of the sun at a place at noon in southern hemi...
We know, T.B.=M.B.+Declination if east
T.B.=M.B. - Declination if west
180=167+13
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If the magnetic bearing of the sun at a place at noon in southern hemi...
Magnetic Bearing and Declination
Magnetic bearing refers to the angle between magnetic north and an object being observed. It is measured clockwise from magnetic north.
Magnetic declination, on the other hand, refers to the angle between true north and magnetic north at a particular location. It is measured in degrees and can be either east or west.
Solution
Given that the magnetic bearing of the sun at a place at noon in the southern hemisphere is 167, we need to find the magnetic declination at that place.
Since the magnetic bearing is given in degrees, we can assume that it is measured from magnetic north. Therefore, we need to subtract the magnetic bearing from 360 to get the magnetic declination.
360 - 167 = 193
However, we also need to determine whether the magnetic declination is east or west. To do this, we can use the following rule:
If the magnetic bearing is more than the true bearing (i.e., the object being observed is west of magnetic north), then the magnetic declination is east.
If the magnetic bearing is less than the true bearing (i.e., the object being observed is east of magnetic north), then the magnetic declination is west.
In this case, we don't know the true bearing of the sun, but we do know that it is at noon. Since the sun is directly overhead at noon at the equator, we can assume that it is south of the observer in the southern hemisphere. Therefore, the sun must be east of magnetic north.
Therefore, the magnetic declination at that place is 13 degrees east (option C).
Magnetic bearing refers to the angle between magnetic north and an object being observed. It is measured clockwise from magnetic north.
Magnetic declination, on the other hand, refers to the angle between true north and magnetic north at a particular location. It is measured in degrees and can be either east or west.
Solution
Given that the magnetic bearing of the sun at a place at noon in the southern hemisphere is 167, we need to find the magnetic declination at that place.
Since the magnetic bearing is given in degrees, we can assume that it is measured from magnetic north. Therefore, we need to subtract the magnetic bearing from 360 to get the magnetic declination.
360 - 167 = 193
However, we also need to determine whether the magnetic declination is east or west. To do this, we can use the following rule:
If the magnetic bearing is more than the true bearing (i.e., the object being observed is west of magnetic north), then the magnetic declination is east.
If the magnetic bearing is less than the true bearing (i.e., the object being observed is east of magnetic north), then the magnetic declination is west.
In this case, we don't know the true bearing of the sun, but we do know that it is at noon. Since the sun is directly overhead at noon at the equator, we can assume that it is south of the observer in the southern hemisphere. Therefore, the sun must be east of magnetic north.
Therefore, the magnetic declination at that place is 13 degrees east (option C).
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If the magnetic bearing of the sun at a place at noon in southern hemisphere is 167º, the magnetic declination at that place isa)77º Nb)23º Sc)13º Ed)13º WCorrect answer is option 'C'. Can you explain this answer?
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