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Passage II
Titanium (II) oxide has a rock salt structure. X-ray diffraction data shows that the length of one edge of the cubic unit cell for TiO with 1:1 ratio of Ti to O is 418 pm and the density is 4.92 g cm-3. ( Atomic mass of Ti = 48).
Q.
Defect present in the crystal is of the type
- a)Schottky
- b)Frenkel
- c)metal excess
- d)metal deficiency
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Passage IITitanium (II) oxide has a rock salt structure. X-ray diffrac...
Rock salt (NaCl) is fcc type structure, z = 4
M = 64 g mol-1, a = 418 pm
theoretical density (d) = 
= 5.82 g cm-3
Experimental density = 4.92 g cm-3
thus, experimental density << theoretical density
thus, there is vacancy in the crystal
d= Mass / Volume
Due to decrease in density, molar mass should decrease. this indicates Schottky defect.
Let Schottky defect be x%
Most Upvoted Answer
Passage IITitanium (II) oxide has a rock salt structure. X-ray diffrac...
The Defect Present in the Crystal is of the Type Frenkel
Given Information:
- Titanium (II) oxide (TiO) has a rock salt structure.
- X-ray diffraction data shows that the length of one edge of the cubic unit cell for TiO with a 1:1 ratio of Ti to O is 418 pm.
- The density of TiO is 4.92 g cm-3.
- The atomic mass of Ti is 48.
Explanation:
Rock Salt Structure:
The rock salt structure is a type of crystal structure in which the cations and anions are arranged in a cubic close-packed structure. In this structure, each cation is surrounded by six anions, and each anion is surrounded by six cations.
Calculating the Number of Ti and O Atoms:
Since the ratio of Ti to O in TiO is 1:1, the number of Ti and O atoms in the unit cell will be the same.
Calculating the Volume of the Unit Cell:
The length of one edge of the cubic unit cell is given as 418 pm. Since it is a cube, the volume of the unit cell can be calculated as the cube of the length of one edge.
Volume of the unit cell = (418 pm)^3 = 74,807,352 pm^3
Converting the Volume to cm^3:
1 pm = 10^-10 m = 10^-8 cm
Volume of the unit cell = 74,807,352 pm^3 * (10^-8 cm/pm)^3 = 7.4807352 cm^3
Calculating the Number of Formula Units in the Unit Cell:
The molecular weight of TiO can be calculated as follows:
Molecular weight of TiO = (Atomic mass of Ti) + (Atomic mass of O)
= 48 + 16 = 64 g/mol
The number of formula units in the unit cell can be calculated using the Avogadro's number:
Number of formula units = (Number of atoms in the unit cell) / (Number of atoms in 1 mole)
= (Number of atoms in the unit cell) / (6.022 x 10^23 atoms/mol)
Calculating the Density:
The density of a substance is given by the formula:
Density = (Mass of the substance) / (Volume of the substance)
In this case, the mass of the substance can be calculated as follows:
Mass of the substance = (Number of formula units) * (Molecular weight of TiO)
Now, we can substitute the given values to calculate the density:
Density = (Number of formula units) * (Molecular weight of TiO) / (Volume of the unit cell)
Calculating the Density:
Substituting the given values:
4.92 g cm-3 = (Number of formula units) * (64 g/mol) / (7.4807352 cm^3)
Simplifying the equation:
(Number of formula units) = (4.92 g cm-3) * (7.4807352 cm^3) / (64 g/mol)
Calculating the number of formula units:
(Number of formula units) = 0.571
Given Information:
- Titanium (II) oxide (TiO) has a rock salt structure.
- X-ray diffraction data shows that the length of one edge of the cubic unit cell for TiO with a 1:1 ratio of Ti to O is 418 pm.
- The density of TiO is 4.92 g cm-3.
- The atomic mass of Ti is 48.
Explanation:
Rock Salt Structure:
The rock salt structure is a type of crystal structure in which the cations and anions are arranged in a cubic close-packed structure. In this structure, each cation is surrounded by six anions, and each anion is surrounded by six cations.
Calculating the Number of Ti and O Atoms:
Since the ratio of Ti to O in TiO is 1:1, the number of Ti and O atoms in the unit cell will be the same.
Calculating the Volume of the Unit Cell:
The length of one edge of the cubic unit cell is given as 418 pm. Since it is a cube, the volume of the unit cell can be calculated as the cube of the length of one edge.
Volume of the unit cell = (418 pm)^3 = 74,807,352 pm^3
Converting the Volume to cm^3:
1 pm = 10^-10 m = 10^-8 cm
Volume of the unit cell = 74,807,352 pm^3 * (10^-8 cm/pm)^3 = 7.4807352 cm^3
Calculating the Number of Formula Units in the Unit Cell:
The molecular weight of TiO can be calculated as follows:
Molecular weight of TiO = (Atomic mass of Ti) + (Atomic mass of O)
= 48 + 16 = 64 g/mol
The number of formula units in the unit cell can be calculated using the Avogadro's number:
Number of formula units = (Number of atoms in the unit cell) / (Number of atoms in 1 mole)
= (Number of atoms in the unit cell) / (6.022 x 10^23 atoms/mol)
Calculating the Density:
The density of a substance is given by the formula:
Density = (Mass of the substance) / (Volume of the substance)
In this case, the mass of the substance can be calculated as follows:
Mass of the substance = (Number of formula units) * (Molecular weight of TiO)
Now, we can substitute the given values to calculate the density:
Density = (Number of formula units) * (Molecular weight of TiO) / (Volume of the unit cell)
Calculating the Density:
Substituting the given values:
4.92 g cm-3 = (Number of formula units) * (64 g/mol) / (7.4807352 cm^3)
Simplifying the equation:
(Number of formula units) = (4.92 g cm-3) * (7.4807352 cm^3) / (64 g/mol)
Calculating the number of formula units:
(Number of formula units) = 0.571
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Passage IITitanium (II) oxide has a rock salt structure. X-ray diffraction data shows that the length of one edge of the cubic unit cell for TiO with 1:1 ratio of Ti to O is 418 pm and the density is 4.92 g cm-3. ( Atomic mass of Ti = 48).Q.Defect present in the crystal is of the typea)Schottkyb)Frenkelc)metal excessd)metal deficiencyCorrect answer is option 'B'. Can you explain this answer?
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Passage IITitanium (II) oxide has a rock salt structure. X-ray diffraction data shows that the length of one edge of the cubic unit cell for TiO with 1:1 ratio of Ti to O is 418 pm and the density is 4.92 g cm-3. ( Atomic mass of Ti = 48).Q.Defect present in the crystal is of the typea)Schottkyb)Frenkelc)metal excessd)metal deficiencyCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Passage IITitanium (II) oxide has a rock salt structure. X-ray diffraction data shows that the length of one edge of the cubic unit cell for TiO with 1:1 ratio of Ti to O is 418 pm and the density is 4.92 g cm-3. ( Atomic mass of Ti = 48).Q.Defect present in the crystal is of the typea)Schottkyb)Frenkelc)metal excessd)metal deficiencyCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Passage IITitanium (II) oxide has a rock salt structure. X-ray diffraction data shows that the length of one edge of the cubic unit cell for TiO with 1:1 ratio of Ti to O is 418 pm and the density is 4.92 g cm-3. ( Atomic mass of Ti = 48).Q.Defect present in the crystal is of the typea)Schottkyb)Frenkelc)metal excessd)metal deficiencyCorrect answer is option 'B'. Can you explain this answer?.
Passage IITitanium (II) oxide has a rock salt structure. X-ray diffraction data shows that the length of one edge of the cubic unit cell for TiO with 1:1 ratio of Ti to O is 418 pm and the density is 4.92 g cm-3. ( Atomic mass of Ti = 48).Q.Defect present in the crystal is of the typea)Schottkyb)Frenkelc)metal excessd)metal deficiencyCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Passage IITitanium (II) oxide has a rock salt structure. X-ray diffraction data shows that the length of one edge of the cubic unit cell for TiO with 1:1 ratio of Ti to O is 418 pm and the density is 4.92 g cm-3. ( Atomic mass of Ti = 48).Q.Defect present in the crystal is of the typea)Schottkyb)Frenkelc)metal excessd)metal deficiencyCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Passage IITitanium (II) oxide has a rock salt structure. X-ray diffraction data shows that the length of one edge of the cubic unit cell for TiO with 1:1 ratio of Ti to O is 418 pm and the density is 4.92 g cm-3. ( Atomic mass of Ti = 48).Q.Defect present in the crystal is of the typea)Schottkyb)Frenkelc)metal excessd)metal deficiencyCorrect answer is option 'B'. Can you explain this answer?.
Solutions for Passage IITitanium (II) oxide has a rock salt structure. X-ray diffraction data shows that the length of one edge of the cubic unit cell for TiO with 1:1 ratio of Ti to O is 418 pm and the density is 4.92 g cm-3. ( Atomic mass of Ti = 48).Q.Defect present in the crystal is of the typea)Schottkyb)Frenkelc)metal excessd)metal deficiencyCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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Passage IITitanium (II) oxide has a rock salt structure. X-ray diffraction data shows that the length of one edge of the cubic unit cell for TiO with 1:1 ratio of Ti to O is 418 pm and the density is 4.92 g cm-3. ( Atomic mass of Ti = 48).Q.Defect present in the crystal is of the typea)Schottkyb)Frenkelc)metal excessd)metal deficiencyCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Passage IITitanium (II) oxide has a rock salt structure. X-ray diffraction data shows that the length of one edge of the cubic unit cell for TiO with 1:1 ratio of Ti to O is 418 pm and the density is 4.92 g cm-3. ( Atomic mass of Ti = 48).Q.Defect present in the crystal is of the typea)Schottkyb)Frenkelc)metal excessd)metal deficiencyCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Passage IITitanium (II) oxide has a rock salt structure. X-ray diffraction data shows that the length of one edge of the cubic unit cell for TiO with 1:1 ratio of Ti to O is 418 pm and the density is 4.92 g cm-3. ( Atomic mass of Ti = 48).Q.Defect present in the crystal is of the typea)Schottkyb)Frenkelc)metal excessd)metal deficiencyCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Passage IITitanium (II) oxide has a rock salt structure. X-ray diffraction data shows that the length of one edge of the cubic unit cell for TiO with 1:1 ratio of Ti to O is 418 pm and the density is 4.92 g cm-3. ( Atomic mass of Ti = 48).Q.Defect present in the crystal is of the typea)Schottkyb)Frenkelc)metal excessd)metal deficiencyCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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