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What is the force of intraction between the proton and the electron in a hydrogen atom? Given charge of electron=4.8*10^10 esu, avarage radius of the orbit of the electron=10^-8cm Calculation pls?
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What is the force of intraction between the proton and the electron in...
Calculation of Force of Interaction between Proton and Electron in Hydrogen Atom


Given data:


  • Charge of electron (q) = 4.8 x 10^10 esu

  • Average radius of the orbit of electron (r) = 10^-8 cm



Formula

The force of interaction between the proton and electron in a hydrogen atom is given by Coulomb's law:

F = (k * q1 * q2) / r^2


where k is the Coulomb's constant, q1 and q2 are the charges of the two particles, and r is the distance between them.


Calculation


For hydrogen atom, the proton and electron have opposite charges. The charge of the proton is equal in magnitude but opposite in sign to that of the electron.


Therefore, q1 = 1.6 x 10^-19 C (charge of proton) and q2 = -1.6 x 10^-19 C (charge of electron).


Substituting the values in the formula:

F = (k * q1 * q2) / r^2

F = (9 x 10^9 Nm^2/C^2) * (1.6 x 10^-19 C) * (-1.6 x 10^-19 C) / (10^-16 m^2)

F = -2.3 x 10^-8 N


Therefore, the force of interaction between the proton and electron in a hydrogen atom is -2.3 x 10^-8 N (attractive force).


Explanation

The force of interaction between the proton and electron in a hydrogen atom is due to the electrostatic force of attraction between them. Coulomb's law describes the magnitude of this force, which depends on the charges of the particles and the distance between them. In a hydrogen atom, the proton and electron are bound together by this force, which keeps the electron in its orbit around the nucleus. The calculated force of interaction (-2.3 x 10^-8 N) is small but sufficient to maintain the stability of the atom.
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Read the following text and answer the following questions on the basis of the same:Band theory of solid:Consider that the Si or Ge crystal contains N atoms. Electrons of each atom will have discrete energies in different orbits. The electron energy will be same if all the atoms are isolated, i.e., separated from each other by a large distance. However, in a crystal, the atoms are close to each other (2 Å to 3 Å) and therefore the electrons interact with each other and also with the neighbouring atomic cores. The overlap (or interaction) will be more felt by the electrons in the outermost orbit while the inner orbit or core electron energies may remain unaffected. Therefore, for understanding electron energies in Si or Ge crystal, we need to consider the changes in the energies of the electrons in the outermost orbit only. For Si, the outermost orbit is the third orbit (n = 3), while for Ge it is the fourth orbit (n = 4). The number of electrons in the outermost orbit is 4 (2s and 2p electrons). Hence, the total number of outer electrons in the crystal is 4N. The maximum possible number of outer electrons in the orbit is 8 (2s + 6p electrons). So, out of the 4N electrons, 2N electrons are in the 2N s-states (orbital quantum number l = 0) and 2N electrons are in the available 6N p-states. Obviously, some p-electron states are empty. This is the case of well separated or isolated atoms.Q. In a crystal, the distance between two atoms is

Read the following text and answer the following questions on the basis of the same:Band theory of solid:Consider that the Si or Ge crystal contains N atoms. Electrons of each atom will have discrete energies in different orbits. The electron energy will be same if all the atoms are isolated, i.e., separated from each other by a large distance. However, in a crystal, the atoms are close to each other (2 Å to 3 Å) and therefore the electrons interact with each other and also with the neighbouring atomic cores. The overlap (or interaction) will be more felt by the electrons in the outermost orbit while the inner orbit or core electron energies may remain unaffected. Therefore, for understanding electron energies in Si or Ge crystal, we need to consider the changes in the energies of the electrons in the outermost orbit only. For Si, the outermost orbit is the third orbit (n = 3), while for Ge it is the fourth orbit (n = 4). The number of electrons in the outermost orbit is 4 (2s and 2p electrons). Hence, the total number of outer electrons in the crystal is 4N. The maximum possible number of outer electrons in the orbit is 8 (2s + 6p electrons). So, out of the 4N electrons, 2N electrons are in the 2N s-states (orbital quantum number l = 0) and 2N electrons are in the available 6N p-states. Obviously, some p-electron states are empty. This is the case of well separated or isolated atoms.Q. The overlap (or interaction) will be more felt by the electrons when they are

What is the force of intraction between the proton and the electron in a hydrogen atom? Given charge of electron=4.8*10^10 esu, avarage radius of the orbit of the electron=10^-8cm Calculation pls?
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What is the force of intraction between the proton and the electron in a hydrogen atom? Given charge of electron=4.8*10^10 esu, avarage radius of the orbit of the electron=10^-8cm Calculation pls? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about What is the force of intraction between the proton and the electron in a hydrogen atom? Given charge of electron=4.8*10^10 esu, avarage radius of the orbit of the electron=10^-8cm Calculation pls? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the force of intraction between the proton and the electron in a hydrogen atom? Given charge of electron=4.8*10^10 esu, avarage radius of the orbit of the electron=10^-8cm Calculation pls?.
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