**Introduction:**

Albinism is an inherited genetic disorder characterized by a lack of melanin production, resulting in little or no pigmentation in the skin, hair, and eyes. It is caused by mutations in genes involved in the production of melanin.

Blood type is determined by the presence or absence of certain antigens on the surface of red blood cells. There are four main blood types: A, B, AB, and O. The AB blood type is inherited when both parents pass on the A and B antigens to their child.

In this scenario, both parents are carriers for albinism and have blood type AB. We need to determine the chances of their offspring having normal pigmentation and AB blood type.

**Inheritance of Albinism:**

Albinism is an autosomal recessive trait, which means that both copies of the gene must be mutated for the disorder to be expressed. In this case, both parents are carriers, meaning they have one normal copy and one mutated copy of the albinism gene.

When both parents are carriers, there are three possible genotypes for their offspring:

1. Normal pigmentation and not a carrier (AA) - This occurs when the child receives a normal copy of the albinism gene from both parents.
2. Normal pigmentation and carrier for albinism (Aa) - This occurs when the child receives a normal copy of the albinism gene from one parent and a mutated copy from the other parent.
3. Albinism (aa) - This occurs when the child receives a mutated copy of the albinism gene from both parents.

**Inheritance of Blood Type:**

The AB blood type is inherited when both parents pass on the A and B antigens to their child. The A and B antigens are codominant, meaning they both contribute to the blood type.

When both parents have blood type AB, there is only one possible genotype for their offspring:

1. AB blood type - This occurs when the child receives the A antigen from one parent and the B antigen from the other parent.

**Calculating the Chances:**

To calculate the chances of the offspring having normal pigmentation and AB blood type, we need to consider the inheritance of both traits separately.

For pigmentation:
- There are three possible genotypes for pigmentation: AA, Aa, and aa.
- The chances of the offspring having normal pigmentation (AA or Aa) is 2 out of 3 (AA + Aa = 2/3).
- The chances of the offspring having albinism (aa) is 1 out of 3 (aa = 1/3).

For blood type:
- There is only one possible genotype for blood type: AB.
- The chances of the offspring having AB blood type is 1 out of 1 (AB = 1/1).

To calculate the overall chances of the offspring having both normal pigmentation and AB blood type, we multiply the chances for each trait together:

Chances of normal pigmentation (2/3) x Chances of AB blood type (1/1) = 2/3.

Therefore, the chances of the offspring having normal pigmentation and AB blood type is 2/3.

**Conclusion:**

The chances of the offspring having normal pigmentation and AB blood type when both parents are carriers for albinism and have blood type AB is 2/3. This