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The figure shows P-V plot of an ideal gas taken through a cycle ABCDA.The part ABC is a semi circle and CDA is half of an ellipse then, a) the process during the path A->B is isothermal b) heat flows out of the gas during the path B->C->D c) work done during the path A->B->C is zero d) positive work is done by the gas in the cycle ABCDA?
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The figure shows P-V plot of an ideal gas taken through a cycle ABCDA....
Explanation of the given figure:

  • The figure shows a P-V plot of an ideal gas taken through a cycle ABCDA.

  • The path ABC is a semi-circle and CDA is half of an ellipse.



Answering the given questions:

  • a) The process during the path A->B is isothermal:

  • The process during the path A->B is isothermal because the path is a semi-circle and the temperature remains constant during the process. As per the first law of thermodynamics, the change in internal energy of an ideal gas is directly proportional to the amount of heat supplied or removed from it, while keeping the volume constant. As the volume is changing, but the temperature is constant, there is no change in internal energy, and hence the process is isothermal.


  • b) Heat flows out of the gas during the path B->C->D:

  • The path B->C->D is in the clockwise direction, and the area enclosed by this path is negative. By the second law of thermodynamics, the area enclosed in the clockwise direction represents the heat flow out of the gas. Thus, heat flows out of the gas during the path B->C->D.


  • c) Work done during the path A->B->C is zero:

  • The path A->B->C is a closed path, and the area enclosed by this path is zero. As per the first law of thermodynamics, the net work done by or on an ideal gas in a closed path is zero. Thus, the work done during the path A->B->C is zero.


  • d) Positive work is done by the gas in the cycle ABCDA:

  • From the figure, it is clear that the area enclosed by the cycle ABCDA is positive. As per the second law of thermodynamics, the area enclosed in the counterclockwise direction represents the net work done by the gas in the cycle. Thus, positive work is done by the gas in the cycle ABCDA.

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The figure shows P-V plot of an ideal gas taken through a cycle ABCDA.The part ABC is a semi circle and CDA is half of an ellipse then, a) the process during the path A->B is isothermal b) heat flows out of the gas during the path B->C->D c) work done during the path A->B->C is zero d) positive work is done by the gas in the cycle ABCDA?
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The figure shows P-V plot of an ideal gas taken through a cycle ABCDA.The part ABC is a semi circle and CDA is half of an ellipse then, a) the process during the path A->B is isothermal b) heat flows out of the gas during the path B->C->D c) work done during the path A->B->C is zero d) positive work is done by the gas in the cycle ABCDA? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The figure shows P-V plot of an ideal gas taken through a cycle ABCDA.The part ABC is a semi circle and CDA is half of an ellipse then, a) the process during the path A->B is isothermal b) heat flows out of the gas during the path B->C->D c) work done during the path A->B->C is zero d) positive work is done by the gas in the cycle ABCDA? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The figure shows P-V plot of an ideal gas taken through a cycle ABCDA.The part ABC is a semi circle and CDA is half of an ellipse then, a) the process during the path A->B is isothermal b) heat flows out of the gas during the path B->C->D c) work done during the path A->B->C is zero d) positive work is done by the gas in the cycle ABCDA?.
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