Explain acidic dehydration with an example?
A dehydration reaction is a chemical reaction between two compounds where one of the products is water. For example, two monomers may react where a hydrogen (H) from one monomer binds to a hydroxyl group (OH) from the other monomer to form a dimer and a water molecule (H2O). The hydroxyl group is a poor leaving group, so Bronsted acid catalysts may be used to help to protonate the hydroxyl to form -OH2+. The reverse reaction, where water combines with hydroxyl groups, is termed hydrolysis or a hydration reaction.
Chemicals commonly used as dehydrating agents include concentrated phosphoric acid, concentrated sulfuric acid, hot ceramic and hot aluminum oxide.
A dehydration reaction is the same as a dehydration synthesis. A dehydration reaction may also be known as a condensation reaction, but more properly, a dehydration reaction is a specific type of condensation reaction.
This question is part of UPSC exam. View all Class 11 courses
Explain acidic dehydration with an example?
Acidic Dehydration: Introduction
Acidic dehydration is a chemical reaction in which a molecule loses water or another small molecule through the action of an acid catalyst. It is a widely used method in organic chemistry to form unsaturated compounds, such as alkenes, from their corresponding alcohols. This reaction is an example of an elimination reaction, where a small molecule is removed from a larger molecule.
The Mechanism of Acidic Dehydration
The acidic dehydration reaction involves several steps:
1. Protonation: The acid catalyst, usually a strong mineral acid like sulfuric acid (H2SO4) or phosphoric acid (H3PO4), donates a proton (H+) to the hydroxyl group (-OH) of the alcohol. This protonation makes the hydroxyl group a better leaving group.
2. Carbocation formation: The protonated alcohol undergoes a rearrangement, resulting in the formation of a carbocation. A carbocation is a positively charged carbon atom with three bonds and an empty p-orbital.
3. Loss of water: The carbocation then loses a water molecule, where the positively charged carbon atom forms a double bond with one of its neighboring carbon atoms. The water molecule is eliminated as a leaving group.
4. Deprotonation: Finally, a base, such as water or an alkoxide ion, abstracts a proton from the neighboring carbon atom, resulting in the formation of the alkene.
Example: Dehydration of Ethanol to Ethene
Let's consider the dehydration of ethanol (C2H5OH) to ethene (C2H4) as an example:
1. In the presence of a strong acid catalyst, such as concentrated sulfuric acid (H2SO4), ethanol undergoes protonation. The acid donates a proton (H+) to the oxygen atom of the hydroxyl group, forming ethyl oxonium ion.
2. The protonated ethanol then rearranges by shifting the bonding electrons, leading to the formation of a stable carbocation called the ethyl carbocation.
3. The ethyl carbocation loses a water molecule, resulting in the formation of ethene. The positively charged carbon atom forms a double bond with the neighboring carbon atom.
4. Finally, a base, such as water or an alkoxide ion, deprotonates the neighboring carbon atom, resulting in the formation of ethene.
Overall, the reaction can be represented as follows:
C2H5OH → C2H4 + H2O
Conclusion
Acidic dehydration is a useful reaction for the synthesis of unsaturated compounds, such as alkenes, from alcohols. It involves protonation, carbocation formation, loss of water, and deprotonation. The reaction is typically catalyzed by strong mineral acids and requires careful control of reaction conditions to achieve the desired product.
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.