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A toroidal solenoid with 500 turns is wound on a ring with a mean radius of 2.90 cm. Find the current in the winding that is required to set up a magnetic field of 0.350 T in the ring if the ring is made of annealed iron Km=1400
- a)82.5mA
- b)72.5mA
- c)79.5mA
- d)69.5mA
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A toroidal solenoid with 500 turns is wound on a ring with a mean radi...
Given,
Number of turns, N = 500 turns
Radius of solenoid, r = 2.9
Relative permeability of annealed iron of Km=1400
Permeability of free space, μ0 =4π
The magnetic field, B=0.350 T
Therefore,
μ/μ0= μr
μ= μr x μ0
B= μrμ0NI/2πR
0.350=1400x4x 3.14x500xI/2xπx2.90
I=72.mA
Number of turns, N = 500 turns
Radius of solenoid, r = 2.9
Relative permeability of annealed iron of Km=1400
Permeability of free space, μ0 =4π
The magnetic field, B=0.350 T
Therefore,
μ/μ0= μr
μ= μr x μ0
B= μrμ0NI/2πR
0.350=1400x4x 3.14x500xI/2xπx2.90
I=72.mA
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Community Answer
A toroidal solenoid with 500 turns is wound on a ring with a mean radi...
Given:
Number of turns, N = 500
Mean radius, r = 2.90 cm
Magnetic field, B = 0.350 T
Magnetic permeability of annealed iron, Km = 1400
To find: Current in the winding required to set up the given magnetic field in the ring
Formula used:
Magnetic field inside a toroid, B = (μ * N * I) / (2π * r)
where μ is the magnetic permeability of the material inside the toroid, N is the number of turns, I is the current in the winding, and r is the mean radius of the toroid.
Solution:
1. Substitute the given values in the formula to find the current in the winding.
0.350 = (1400 * 500 * I) / (2π * 2.90)
2. Simplify the equation by multiplying both sides with (2π * 2.90).
0.350 * 2π * 2.90 = 1400 * 500 * I
I = (0.350 * 2π * 2.90) / (1400 * 500)
I = 72.5 mA
Therefore, the current in the winding required to set up the given magnetic field in the ring is 72.5 mA.
Answer: Option (B) 72.5 mA.
Number of turns, N = 500
Mean radius, r = 2.90 cm
Magnetic field, B = 0.350 T
Magnetic permeability of annealed iron, Km = 1400
To find: Current in the winding required to set up the given magnetic field in the ring
Formula used:
Magnetic field inside a toroid, B = (μ * N * I) / (2π * r)
where μ is the magnetic permeability of the material inside the toroid, N is the number of turns, I is the current in the winding, and r is the mean radius of the toroid.
Solution:
1. Substitute the given values in the formula to find the current in the winding.
0.350 = (1400 * 500 * I) / (2π * 2.90)
2. Simplify the equation by multiplying both sides with (2π * 2.90).
0.350 * 2π * 2.90 = 1400 * 500 * I
I = (0.350 * 2π * 2.90) / (1400 * 500)
I = 72.5 mA
Therefore, the current in the winding required to set up the given magnetic field in the ring is 72.5 mA.
Answer: Option (B) 72.5 mA.
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Solutions for A toroidal solenoid with 500 turns is wound on a ring with a mean radius of 2.90 cm. Find the current in the winding that is required to set up a magnetic field of 0.350 T in the ring if the ring is made of annealed ironKm=1400a)82.5mAb)72.5mAc)79.5mAd)69.5mACorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
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