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A wooden cube just floats inside water with a 200gm mass placed on it.When the mass is removed,the cube floats with its top surface 2 cm above the water level.What is the side of the cube?
Most Upvoted Answer
A wooden cube just floats inside water with a 200gm mass placed on it....
Volume of cube=area× height
200=x^2 × 2
x^2= 200÷2
x^2 = 100
therefore; x=10 cm...!!hope u clear..!😊
200=x^2 × 2
x^2= 200÷2
x^2 = 100
therefore; x=10 cm...!!hope u clear..!😊
Community Answer
A wooden cube just floats inside water with a 200gm mass placed on it....
Given:
Mass of object (m) = 200 gm
Distance of cube from water level (h) = 2 cm
To find:
Length of the side of the cube (s)
Assumption:
Assuming density of water to be 1 gm/cm³
Solution:
Step 1: Calculate the weight of the object
Weight of object (w) = m * g, where g = 9.8 m/s²
Weight of object (w) = 200/1000 * 9.8 = 1.96 N
Step 2: Calculate the buoyant force on the cube when the object is placed on it
Buoyant force (Fb) = weight of water displaced by the cube
Volume of cube (V) = s³
Weight of water displaced by the cube (W) = V * density of water * g
Weight of water displaced by the cube (W) = s³ * 1 * 9.8
Weight of water displaced by the cube (W) = 9.8 s³
Buoyant force (Fb) = 9.8 s³
Net upward force on the cube (Fn) when the object is placed on it
Fn = Fb - w
Fn = 9.8 s³ - 1.96
Step 3: Calculate the volume of water displaced by the cube when the object is removed
Volume of water displaced by the cube = s² * h
Step 4: Calculate the buoyant force on the cube when the object is removed
Buoyant force (Fb) = weight of water displaced by the cube
Weight of water displaced by the cube (W) = V * density of water * g
Weight of water displaced by the cube (W) = s³ * 1 * 9.8
Weight of water displaced by the cube (W) = 9.8 s³
Buoyant force (Fb) = 9.8 s³
Step 5: Calculate the net upward force on the cube when the object is removed
Fn = Fb
Fn = 9.8 s³
Step 6: Equate the net upward force on the cube when the object is placed on it and when it is removed
9.8 s³ - 1.96 = 9.8 s³
1.96 = 9.8 s³ - 9.8 s³
1.96 = 0
Conclusion:
The above equation is not possible. Therefore, the cube cannot float with its top surface 2 cm above the water level when the object is removed. Hence, the given information is not possible.
Mass of object (m) = 200 gm
Distance of cube from water level (h) = 2 cm
To find:
Length of the side of the cube (s)
Assumption:
Assuming density of water to be 1 gm/cm³
Solution:
Step 1: Calculate the weight of the object
Weight of object (w) = m * g, where g = 9.8 m/s²
Weight of object (w) = 200/1000 * 9.8 = 1.96 N
Step 2: Calculate the buoyant force on the cube when the object is placed on it
Buoyant force (Fb) = weight of water displaced by the cube
Volume of cube (V) = s³
Weight of water displaced by the cube (W) = V * density of water * g
Weight of water displaced by the cube (W) = s³ * 1 * 9.8
Weight of water displaced by the cube (W) = 9.8 s³
Buoyant force (Fb) = 9.8 s³
Net upward force on the cube (Fn) when the object is placed on it
Fn = Fb - w
Fn = 9.8 s³ - 1.96
Step 3: Calculate the volume of water displaced by the cube when the object is removed
Volume of water displaced by the cube = s² * h
Step 4: Calculate the buoyant force on the cube when the object is removed
Buoyant force (Fb) = weight of water displaced by the cube
Weight of water displaced by the cube (W) = V * density of water * g
Weight of water displaced by the cube (W) = s³ * 1 * 9.8
Weight of water displaced by the cube (W) = 9.8 s³
Buoyant force (Fb) = 9.8 s³
Step 5: Calculate the net upward force on the cube when the object is removed
Fn = Fb
Fn = 9.8 s³
Step 6: Equate the net upward force on the cube when the object is placed on it and when it is removed
9.8 s³ - 1.96 = 9.8 s³
1.96 = 9.8 s³ - 9.8 s³
1.96 = 0
Conclusion:
The above equation is not possible. Therefore, the cube cannot float with its top surface 2 cm above the water level when the object is removed. Hence, the given information is not possible.
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A wooden cube just floats inside water with a 200gm mass placed on it.When the mass is removed,the cube floats with its top surface 2 cm above the water level.What is the side of the cube? for NEET 2026 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A wooden cube just floats inside water with a 200gm mass placed on it.When the mass is removed,the cube floats with its top surface 2 cm above the water level.What is the side of the cube? covers all topics & solutions for NEET 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A wooden cube just floats inside water with a 200gm mass placed on it.When the mass is removed,the cube floats with its top surface 2 cm above the water level.What is the side of the cube?.
A wooden cube just floats inside water with a 200gm mass placed on it.When the mass is removed,the cube floats with its top surface 2 cm above the water level.What is the side of the cube? for NEET 2026 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A wooden cube just floats inside water with a 200gm mass placed on it.When the mass is removed,the cube floats with its top surface 2 cm above the water level.What is the side of the cube? covers all topics & solutions for NEET 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A wooden cube just floats inside water with a 200gm mass placed on it.When the mass is removed,the cube floats with its top surface 2 cm above the water level.What is the side of the cube?.
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