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Rate of decrease in distance between two objects moving with certain speed towards each other is 6 m/s and rate of decrease decrease in distance between those objects with same speed when move in some direction is 4 m/s. Then the speeds of objects are . . (A) 5 m/s, 1 m/s (B) 4 m/s, 2 m/s (C) 4 m/s, 1 m/s (D) 5m/s,2m/s?
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Rate of decrease in distance between two objects moving with certain s...
**Given Information:**
- Rate of decrease in distance between two objects moving towards each other = 6 m/s
- Rate of decrease in distance between the objects when moving in some direction = 4 m/s

**Approach:**
Let's assume the speeds of the objects as v1 and v2.

When the objects are moving towards each other, the relative speed is the sum of their individual speeds:
Relative speed = v1 + v2

When the objects are moving in the same direction, the relative speed is the difference of their individual speeds:
Relative speed = v1 - v2

From the given information, we can form the following equations:

1. When the objects are moving towards each other:
Rate of decrease in distance = 6 m/s
Relative speed = v1 + v2

2. When the objects are moving in the same direction:
Rate of decrease in distance = 4 m/s
Relative speed = v1 - v2

**Solution:**

Let's solve the equations to find the values of v1 and v2.

1. When the objects are moving towards each other:
Rate of decrease in distance = 6 m/s
Relative speed = v1 + v2

2. When the objects are moving in the same direction:
Rate of decrease in distance = 4 m/s
Relative speed = v1 - v2

To solve these equations, we can use the method of substitution.

Let's solve equation 1 for v1:
v1 = Rate of decrease in distance - v2

Substitute this value of v1 in equation 2:
Rate of decrease in distance = 4 m/s
Relative speed = (Rate of decrease in distance - v2) - v2
4 = Rate of decrease in distance - 2v2

Now, substitute the given value of rate of decrease in distance:
4 = 6 - 2v2

Simplify the equation:
2v2 = 6 - 4
2v2 = 2
v2 = 1 m/s

Now, substitute this value of v2 in equation 1 to find v1:
v1 = Rate of decrease in distance - v2
v1 = 6 - 1
v1 = 5 m/s

Therefore, the speeds of the objects are:
v1 = 5 m/s
v2 = 1 m/s

Hence, the correct answer is option (A) 5 m/s, 1 m/s.
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Rate of decrease in distance between two objects moving with certain speed towards each other is 6 m/s and rate of decrease decrease in distance between those objects with same speed when move in some direction is 4 m/s. Then the speeds of objects are . . (A) 5 m/s, 1 m/s (B) 4 m/s, 2 m/s (C) 4 m/s, 1 m/s (D) 5m/s,2m/s?
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Rate of decrease in distance between two objects moving with certain speed towards each other is 6 m/s and rate of decrease decrease in distance between those objects with same speed when move in some direction is 4 m/s. Then the speeds of objects are . . (A) 5 m/s, 1 m/s (B) 4 m/s, 2 m/s (C) 4 m/s, 1 m/s (D) 5m/s,2m/s? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Rate of decrease in distance between two objects moving with certain speed towards each other is 6 m/s and rate of decrease decrease in distance between those objects with same speed when move in some direction is 4 m/s. Then the speeds of objects are . . (A) 5 m/s, 1 m/s (B) 4 m/s, 2 m/s (C) 4 m/s, 1 m/s (D) 5m/s,2m/s? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Rate of decrease in distance between two objects moving with certain speed towards each other is 6 m/s and rate of decrease decrease in distance between those objects with same speed when move in some direction is 4 m/s. Then the speeds of objects are . . (A) 5 m/s, 1 m/s (B) 4 m/s, 2 m/s (C) 4 m/s, 1 m/s (D) 5m/s,2m/s?.
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