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A gas (Cv,m = ) behaving ideally was allowed to expand reversibly and adiabaticaly from 1 litre to 32 litre. It's initial temperature was 327°C. The molar enthalpy change (in J/mole) for the process is
  • a)
    -1125 R
  • b)
    -575 R
  • c)
    -1575 R
  • d)
    None of these
Correct answer is option 'C'. Can you explain this answer?
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A gas (Cv,m=) behaving ideally was allowed to expand reversibly and ad...

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A gas (Cv,m=) behaving ideally was allowed to expand reversibly and ad...
Since, (t2/t1) =( V1/V2)^(¥ - 1)
but gamma is unknown here.therefore:-
since, [Cp - CV = R]
{ Cp = Cv + R}
since , :-
¥= {Cp/Cv} = (Cv + R) / Cv
=> (5R/2.+ R )/(5R/2) = (7R/2)/(5R/2)
=>(7R/2) x ( 2/ 5R) = 7/5
since,. t2=? , t1= 327+273=600k , V1= 1 , V2 = 32, ¥ = 7/5
therefore
=> (t2/600) = (1/32)^((7/5)-1)
=> (t2/600) = (1/32)^(2/5)
=> (t2/600) = ((1/2)^5)^2/5
=> (t2/600) = (1/4)
=> t2 = 600/4 = 150k
now
molar enthalpy change = nCp∆t
=>.( 7R /2)(150-600)
=>( 7R/2) × (-450)
=> 7R x (-225)
=> - 1575R
therefore option c is the correct
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A gas (Cv,m=) behaving ideally was allowed to expand reversibly and ad...

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A gas (Cv,m=) behaving ideally was allowed to expand reversibly and adiabaticaly from 1 litre to 32 litre. It's initial temperature was 327°C. The molar enthalpy change (in J/mole) for the process isa)-1125 Rb)-575 Rc)-1575 Rd)None of theseCorrect answer is option 'C'. Can you explain this answer?
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