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The maxᵐ no. possible interference maxima for slit separation equal to twice the walvelengh in YDSE is (a)∞ (b)five (c)three (d)zero?
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The maxᵐ no. possible interference maxima for slit separation equal to...
−dsinθ=nλ
d=2λ
2λsinθ=nλ
2sinθ=n
When sinθ=1,n=2*1=2
The interference maxima will be formed when n=0,+1 or -1,+2 or -2.
Therefore the maximum number of possible interference maxima =5
so (b) is the correct option
Community Answer
The maxᵐ no. possible interference maxima for slit separation equal to...
5
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The maxᵐ no. possible interference maxima for slit separation equal to twice the walvelengh in YDSE is (a)∞ (b)five (c)three (d)zero?
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The maxᵐ no. possible interference maxima for slit separation equal to twice the walvelengh in YDSE is (a)∞ (b)five (c)three (d)zero? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The maxᵐ no. possible interference maxima for slit separation equal to twice the walvelengh in YDSE is (a)∞ (b)five (c)three (d)zero? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The maxᵐ no. possible interference maxima for slit separation equal to twice the walvelengh in YDSE is (a)∞ (b)five (c)three (d)zero?.
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