Phase of Particle at t=1s
- To find the phase of the particle at t=1s, we first need to understand the equation of motion given: x=5 sin(πt/2).
- The general equation for simple harmonic motion (SHM) is x = A sin(ωt + φ), where A is the amplitude, ω is the angular frequency, t is the time, and φ is the phase constant.

Identifying the Parameters
- In the given equation x=5 sin(πt/2), the amplitude A = 5 and the angular frequency ω = π/2.
- Comparing this with the general equation, we can see that the phase constant φ is not explicitly given.

Finding the Phase at t=1s
- To find the phase at t=1s, we need to substitute t=1 into the equation x=5 sin(πt/2).
- x = 5 sin(π/2) = 5 sin(π/2) = 5 x 1 = 5.
- Since sin(π/2) = 1, the particle is at x=5 at t=1s.

Conclusion
- Therefore, the phase of the particle at t=1s is such that it is at its maximum displacement of 5 units along the x-axis.
- The phase constant φ in this case is 0, as the particle starts at the maximum displacement when t=0.
- Understanding the phase of the particle helps in determining its position and behavior in simple harmonic motion.