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Focal length of convex lens is 0.1m. A liquid lens is formed between a plane surface and one face of this lens of radius of curvature 0.05m. The converging combination formed is found to have a focal length of 0.2m. Calculate the refractive index of the medium.
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Focal length of convex lens is 0.1m. A liquid lens is formed between a...
**Given Data:**
- Focal length of convex lens: f1 = 0.1 m
- Radius of curvature of one face of the lens: R1 = 0.05 m
- Focal length of the converging combination: f = 0.2 m

**Calculating the Focal Length of the Liquid Lens:**
To find the focal length of the liquid lens, we can use the lensmaker's formula:

$\frac{1}{f} = (n - 1)\left(\frac{1}{R_1} - \frac{1}{R_2}\right)$

Since one of the radii of curvature is infinite for a plane surface, we can simplify the formula:

$\frac{1}{f} = (n - 1)\left(\frac{1}{R_1}\right)$

Substituting the given values:

$\frac{1}{f} = (n - 1)\left(\frac{1}{0.05}\right)$

Simplifying, we get:

$\frac{1}{f} = (n - 1)\left(\frac{1}{0.05}\right)$

$0.2 = (n - 1)\left(\frac{1}{0.05}\right)$

Solving for n, we find:

$n - 1 = \frac{0.2}{\frac{1}{0.05}}$

$n - 1 = 10$

$n = 11$

**Calculating the Refractive Index of the Medium:**
The refractive index of the medium can be calculated using the formula:

$n = \frac{c}{v}$

where c is the speed of light in vacuum and v is the speed of light in the medium.

The speed of light in vacuum is approximately 3 x 10^8 m/s.

The speed of light in the medium can be calculated using the formula:

$v = \frac{1}{f}$

Substituting the given value for f:

$v = \frac{1}{0.2}$

$v = 5$

Substituting the values into the refractive index formula:

$n = \frac{3 \times 10^8}{5}$

$n = 6 \times 10^7$

Therefore, the refractive index of the medium is 6 x 10^7.
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Focal length of convex lens is 0.1m. A liquid lens is formed between a...
Refractive index =8/9
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Focal length of convex lens is 0.1m. A liquid lens is formed between a plane surface and one face of this lens of radius of curvature 0.05m. The converging combination formed is found to have a focal length of 0.2m. Calculate the refractive index of the medium.
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Focal length of convex lens is 0.1m. A liquid lens is formed between a plane surface and one face of this lens of radius of curvature 0.05m. The converging combination formed is found to have a focal length of 0.2m. Calculate the refractive index of the medium. for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Focal length of convex lens is 0.1m. A liquid lens is formed between a plane surface and one face of this lens of radius of curvature 0.05m. The converging combination formed is found to have a focal length of 0.2m. Calculate the refractive index of the medium. covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Focal length of convex lens is 0.1m. A liquid lens is formed between a plane surface and one face of this lens of radius of curvature 0.05m. The converging combination formed is found to have a focal length of 0.2m. Calculate the refractive index of the medium..
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