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27 g of Al will react completely with how many grams of oxygen?(1978)
- a)8 g
- b)16 g
- c)32 g
- d)24 g
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
27 g of Al will react completely with how many grams of oxygen?(1978)a...
4 Al + 3O2 —→ 2 Al2O3
At. wt. of Al = 27 Thus 4 × 27 g of Al reacts with oxygen = 3 × 32 g
∴ 27 g of Al reacts with oxygen =
At. wt. of Al = 27 Thus 4 × 27 g of Al reacts with oxygen = 3 × 32 g
∴ 27 g of Al reacts with oxygen =
= 24 g
Most Upvoted Answer
27 g of Al will react completely with how many grams of oxygen?(1978)a...
Given: Mass of Al = 27 g
To find: Mass of oxygen required to react completely with Al
Balanced Chemical Equation for the reaction between Al and O2:
4 Al + 3 O2 → 2 Al2O3
From the balanced chemical equation, it can be observed that 4 moles of Al reacts with 3 moles of O2 to produce 2 moles of Al2O3.
Molecular mass of Al = 27 g/mol
Molecular mass of O2 = 32 g/mol
Calculation:
Number of moles of Al = Mass of Al / Molecular mass of Al
= 27 g / 27 g/mol
= 1 mole
According to the balanced equation, 4 moles of Al reacts with 3 moles of O2
Therefore, Number of moles of O2 required = (3/4) × 1 mole
= 0.75 mole
Mass of O2 required = Number of moles of O2 × Molecular mass of O2
= 0.75 mole × 32 g/mol
= 24 g
Hence, the mass of oxygen required to react completely with 27 g of Al is 24 g.
Therefore, option (d) 24 g is the correct answer.
To find: Mass of oxygen required to react completely with Al
Balanced Chemical Equation for the reaction between Al and O2:
4 Al + 3 O2 → 2 Al2O3
From the balanced chemical equation, it can be observed that 4 moles of Al reacts with 3 moles of O2 to produce 2 moles of Al2O3.
Molecular mass of Al = 27 g/mol
Molecular mass of O2 = 32 g/mol
Calculation:
Number of moles of Al = Mass of Al / Molecular mass of Al
= 27 g / 27 g/mol
= 1 mole
According to the balanced equation, 4 moles of Al reacts with 3 moles of O2
Therefore, Number of moles of O2 required = (3/4) × 1 mole
= 0.75 mole
Mass of O2 required = Number of moles of O2 × Molecular mass of O2
= 0.75 mole × 32 g/mol
= 24 g
Hence, the mass of oxygen required to react completely with 27 g of Al is 24 g.
Therefore, option (d) 24 g is the correct answer.
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27 g of Al will react completely with how many grams of oxygen?(1978)a)8 gb)16 gc)32 gd)24 gCorrect answer is option 'D'. Can you explain this answer?
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