2 electrons are placed at a distance d such that electrostatic force b...
F = [k (q1)× (q2) ] ÷ [ d²]
here k = 9 × 10^9 ( is constant )
q1 & q2 is chare on electron ,
q1= q2= q = 1.6× 10^(-19) C
F = electrostatic force = sum of weight of both electron
F = m+m = 2m = 2×[ 9.1× 10^(-31) ]
F= k × q² ÷ d² = 2m
=> k × q² ÷ 2m = d²
putting value of k , q and m ,
we get ,
=> d² = 126.59
=> d = 11.25m
2 electrons are placed at a distance d such that electrostatic force b...
**Given Information:**
- Two electrons are placed at a distance d.
- The electrostatic force between the two electrons is equal to the sum of the weight of both electrons.
**Solution:**
To solve this problem, we need to calculate the value of d.
**Step 1:**
We know that the electrostatic force between two point charges can be calculated using Coulomb's Law:
F = (k * q₁ * q₂) / r²
Where:
F is the electrostatic force,
k is the electrostatic constant (9 x 10^9 Nm²/C²),
q₁ and q₂ are the charges of the particles, and
r is the distance between the particles.
**Step 2:**
The weight of an object can be calculated using the formula:
Weight = mass * acceleration due to gravity
For an electron, the mass (m) is 9.1 x 10^-31 kg and the acceleration due to gravity (g) is 9.8 m/s².
**Step 3:**
Given that the electrostatic force between the two electrons is equal to the sum of their weights, we can equate the formulas:
(k * q₁ * q₂) / r² = (m₁ * g) + (m₂ * g)
**Step 4:**
Since both electrons have the same charge (e = 1.6 x 10^-19 C) and mass (m = 9.1 x 10^-31 kg), we can simplify the equation:
(k * e²) / r² = (2 * m * g)
**Step 5:**
Now, we can rearrange the equation to solve for the distance (r):
r² = (k * e²) / (2 * m * g)
r = √((k * e²) / (2 * m * g))
**Step 6:**
Substituting the given values, we can calculate the value of r:
r = √((9 x 10^9 Nm²/C² * (1.6 x 10^-19 C)²) / (2 * (9.1 x 10^-31 kg) * (9.8 m/s²)))
r ≈ 2.64 x 10^-11 meters
Therefore, the value of d is approximately 2.64 x 10^-11 meters.