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Let P(x) = x6 – 3x4 + x2 + 5.Then P(x) = 0
  • a)
    has all real roots
  • b)
    has all imaginary roots
  • c)
    has four real and two imaginary roots
  • d)
    has two real and four imaginary roots
Correct answer is option 'B'. Can you explain this answer?
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Let P(x) = x6 – 3x4 + x2 + 5.Then P(x) = 0a)has all real rootsb)...
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Let P(x) = x6 – 3x4 + x2 + 5.Then P(x) = 0a)has all real rootsb)has all imaginary rootsc)has four real and two imaginary rootsd)has two real and four imaginary rootsCorrect answer is option 'B'. Can you explain this answer?
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Let P(x) = x6 – 3x4 + x2 + 5.Then P(x) = 0a)has all real rootsb)has all imaginary rootsc)has four real and two imaginary rootsd)has two real and four imaginary rootsCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Let P(x) = x6 – 3x4 + x2 + 5.Then P(x) = 0a)has all real rootsb)has all imaginary rootsc)has four real and two imaginary rootsd)has two real and four imaginary rootsCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let P(x) = x6 – 3x4 + x2 + 5.Then P(x) = 0a)has all real rootsb)has all imaginary rootsc)has four real and two imaginary rootsd)has two real and four imaginary rootsCorrect answer is option 'B'. Can you explain this answer?.
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