An electric field E is set up between of a capacitor as shown in figure and an electron enters in the field between the plates with the velocity V the length of each plate is L. find Q of deviation of the path.?

Question

Answer

Answer

Given

Electric field E is set up between the plates of a capacitor

An electron enters the field between the plates with velocity V

The length of each plate is L

To Find

The deviation of the path of the electron

Explanation

When an electron enters an electric field, it experiences a force that is perpendicular to both the velocity of the electron and the electric field. This force is given by the equation:

F = qE

where F is the force on the electron, q is the charge of the electron, and E is the electric field.

As the force is perpendicular to the velocity of the electron, it causes the path of the electron to curve. The deviation of the path can be calculated using the equation:

d = (1/2)qEL^2 / mv^2

where d is the deviation of the path, E is the electric field, L is the length of each plate, m is the mass of the electron, and v is the velocity of the electron.

Substituting Values

We are given that the electric field is E, the length of each plate is L, and the velocity of the electron is V. The charge of the electron is -1.6 x 10^-19 C and the mass of the electron is 9.1 x 10^-31 kg. Substituting these values into the equation for the deviation of the path, we get:

d = (1/2)(-1.6 x 10^-19)(E)(L^2) / (9.1 x 10^-31)(V^2)

Solution

The deviation of the path of the electron is given by the above equation. To solve for the deviation, we need to know the value of the electric field. Once we know the value of the electric field, we can calculate the deviation of the path using the equation above.

Answer

Hry don't have figure please post mew question with figure

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