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Coefficient of correlation is 0.8 and covariance of x y is 60 and standard deviation of y is 2.5 and Sigma x square is 90 and now find the number of items ?
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Coefficient of correlation is 0.8 and covariance of x y is 60 and stan...
Frst we will find out std x by the formula r=cov x,y/std x std y then there is a formula to find out the std x that is std x = sigma x square / N under the root ...i found out the value but i dont knw it is correct or not i got ans 10 but may be my way is correct to find out ...
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Coefficient of correlation is 0.8 and covariance of x y is 60 and stan...
Number of Items

To find the number of items, we can use the formula for the coefficient of correlation (r) and the given information about the covariance and standard deviation.

Formula:
The formula for the coefficient of correlation (r) is given by:

r = Cov(x, y) / (σx * σy)

Where:
- r is the coefficient of correlation
- Cov(x, y) is the covariance between variables x and y
- σx is the standard deviation of variable x
- σy is the standard deviation of variable y

Given Information:
- Coefficient of correlation (r) = 0.8
- Cov(x, y) = 60
- Standard deviation of y (σy) = 2.5
- Sigma x square (σx^2) = 90

Calculating Number of Items:
1. Rearrange the formula for the coefficient of correlation to solve for Cov(x, y):
Cov(x, y) = r * σx * σy

2. Substitute the given values into the formula:
Cov(x, y) = 0.8 * √(90) * 2.5
Cov(x, y) = 0.8 * 3 * 2.5
Cov(x, y) = 6

3. Now, let's use the formula for covariance to find the number of items (n):
Cov(x, y) = Σ((xi - μx) * (yi - μy)) / (n - 1)

Rearrange the formula to solve for n:
n = (Cov(x, y) * (n - 1)) / Σ((xi - μx) * (yi - μy))

4. Substitute the known values into the formula:
6 = (6 * (n - 1)) / 60

5. Solve for n by cross-multiplying and simplifying the equation:
6 * 60 = 6 * (n - 1)
360 = 6n - 6
6n = 366
n = 61

Therefore, the number of items is 61.
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Coefficient of correlation is 0.8 and covariance of x y is 60 and standard deviation of y is 2.5 and Sigma x square is 90 and now find the number of items ?
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Coefficient of correlation is 0.8 and covariance of x y is 60 and standard deviation of y is 2.5 and Sigma x square is 90 and now find the number of items ? for B Com 2024 is part of B Com preparation. The Question and answers have been prepared according to the B Com exam syllabus. Information about Coefficient of correlation is 0.8 and covariance of x y is 60 and standard deviation of y is 2.5 and Sigma x square is 90 and now find the number of items ? covers all topics & solutions for B Com 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Coefficient of correlation is 0.8 and covariance of x y is 60 and standard deviation of y is 2.5 and Sigma x square is 90 and now find the number of items ?.
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