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calculate the freezing point of solution prepared by dissolving 4.5 gm of glucose ( molar mass 180 gmmole inverse) in 250 gm of bromoform
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calculate the freezing point of solution prepared by dissolving 4.5 gm...
Calculation of Freezing Point Depression:
- First, calculate the moles of glucose:
Moles of glucose = Mass of glucose / Molar mass of glucose
= 4.5 g / 180 g/mol
= 0.025 mol
- Next, calculate the molality of the solution:
Molality = Moles of solute / Mass of solvent in kg
= 0.025 mol / 0.250 kg
= 0.1 mol/kg
- Now, determine the freezing point depression constant (Kf) for bromoform, which is 5.12°C kg/mol.
- Use the formula for freezing point depression to calculate the change in freezing point:
ΔTf = Kf * molality
= 5.12°C kg/mol * 0.1 mol/kg
= 0.512°C
- Finally, calculate the freezing point of the solution:
Freezing point of solution = Freezing point of pure solvent - ΔTf
= 0°C - 0.512°C
= -0.512°C
Therefore, the freezing point of the solution prepared by dissolving 4.5 gm of glucose in 250 gm of bromoform is -0.512°C.
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calculate the freezing point of solution prepared by dissolving 4.5 gm of glucose ( molar mass 180 gmmole inverse) in 250 gm of bromoform Related: Colligative Properties: Depression in Freezing point (Part - 27) - Solutions, Chemistry, Class 12?
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