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calculate the freezing point of solution prepared by dissolving 4.5 gm of glucose ( molar mass 180 gmmole inverse) in 250 gm of bromoform
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calculate the freezing point of solution prepared by dissolving 4.5 gm...
Calculation of Freezing Point Depression:
- First, calculate the moles of glucose:
Moles of glucose = Mass of glucose / Molar mass of glucose
= 4.5 g / 180 g/mol
= 0.025 mol
- Next, calculate the molality of the solution:
Molality = Moles of solute / Mass of solvent in kg
= 0.025 mol / 0.250 kg
= 0.1 mol/kg
- Now, determine the freezing point depression constant (Kf) for bromoform, which is 5.12°C kg/mol.
- Use the formula for freezing point depression to calculate the change in freezing point:
ΔTf = Kf * molality
= 5.12°C kg/mol * 0.1 mol/kg
= 0.512°C
- Finally, calculate the freezing point of the solution:
Freezing point of solution = Freezing point of pure solvent - ΔTf
= 0°C - 0.512°C
= -0.512°C
Therefore, the freezing point of the solution prepared by dissolving 4.5 gm of glucose in 250 gm of bromoform is -0.512°C.
- First, calculate the moles of glucose:
Moles of glucose = Mass of glucose / Molar mass of glucose
= 4.5 g / 180 g/mol
= 0.025 mol
- Next, calculate the molality of the solution:
Molality = Moles of solute / Mass of solvent in kg
= 0.025 mol / 0.250 kg
= 0.1 mol/kg
- Now, determine the freezing point depression constant (Kf) for bromoform, which is 5.12°C kg/mol.
- Use the formula for freezing point depression to calculate the change in freezing point:
ΔTf = Kf * molality
= 5.12°C kg/mol * 0.1 mol/kg
= 0.512°C
- Finally, calculate the freezing point of the solution:
Freezing point of solution = Freezing point of pure solvent - ΔTf
= 0°C - 0.512°C
= -0.512°C
Therefore, the freezing point of the solution prepared by dissolving 4.5 gm of glucose in 250 gm of bromoform is -0.512°C.
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calculate the freezing point of solution prepared by dissolving 4.5 gm of glucose ( molar mass 180 gmmole inverse) in 250 gm of bromoform Related: Colligative Properties: Depression in Freezing point (Part - 27) - Solutions, Chemistry, Class 12?
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calculate the freezing point of solution prepared by dissolving 4.5 gm of glucose ( molar mass 180 gmmole inverse) in 250 gm of bromoform Related: Colligative Properties: Depression in Freezing point (Part - 27) - Solutions, Chemistry, Class 12? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about calculate the freezing point of solution prepared by dissolving 4.5 gm of glucose ( molar mass 180 gmmole inverse) in 250 gm of bromoform Related: Colligative Properties: Depression in Freezing point (Part - 27) - Solutions, Chemistry, Class 12? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for calculate the freezing point of solution prepared by dissolving 4.5 gm of glucose ( molar mass 180 gmmole inverse) in 250 gm of bromoform Related: Colligative Properties: Depression in Freezing point (Part - 27) - Solutions, Chemistry, Class 12?.
calculate the freezing point of solution prepared by dissolving 4.5 gm of glucose ( molar mass 180 gmmole inverse) in 250 gm of bromoform Related: Colligative Properties: Depression in Freezing point (Part - 27) - Solutions, Chemistry, Class 12? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about calculate the freezing point of solution prepared by dissolving 4.5 gm of glucose ( molar mass 180 gmmole inverse) in 250 gm of bromoform Related: Colligative Properties: Depression in Freezing point (Part - 27) - Solutions, Chemistry, Class 12? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for calculate the freezing point of solution prepared by dissolving 4.5 gm of glucose ( molar mass 180 gmmole inverse) in 250 gm of bromoform Related: Colligative Properties: Depression in Freezing point (Part - 27) - Solutions, Chemistry, Class 12?.
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