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a person is holding a bucket by applying a force of 10 Newton. he moved a horizontal distance of 5 metre and then come climbs up a vertical distance of 10 metre. find the total work done by him.
Verified Answer
a person is holding a bucket by applying a force of 10 Newton. he move...
Case 1:
force= 10 N
Displacement= 5 m
Work done= FScos(theta)
=10* 5* cos(90)
= 50*0
=0J
Case 2:
Force=10 N
Displacement=10m
Work done=FScos(theta)
= 10*10*cos(180)
=100*-1
=-100
Now, total work done= 0+(-100)
=-100J
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Most Upvoted Answer
a person is holding a bucket by applying a force of 10 Newton. he move...
Calculating Work Done
To calculate the total work done by the person, we need to consider the work done in both horizontal and vertical directions separately, and then find the sum of these two works.
Work Done in the Horizontal Direction
The work done in the horizontal direction can be calculated using the formula:
Work = Force x Distance x Cos(θ)
Where:
- Force is the applied force of 10 Newton
- Distance is the horizontal distance of 5 meters
- θ (Theta) is the angle between the applied force and the direction of motion, which in this case is 0 degrees (cos(0) = 1)
Substituting the given values into the formula:
Work = 10 Newton x 5 meters x 1
= 50 Joules
Therefore, the work done in the horizontal direction is 50 Joules.
Work Done in the Vertical Direction
The work done in the vertical direction can be calculated using the formula:
Work = Force x Distance x Cos(θ)
Where:
- Force is the applied force of 10 Newton
- Distance is the vertical distance of 10 meters
- θ (Theta) is the angle between the applied force and the direction of motion, which in this case is 90 degrees (cos(90) = 0)
Substituting the given values into the formula:
Work = 10 Newton x 10 meters x 0
= 0 Joules
Therefore, the work done in the vertical direction is 0 Joules.
Total Work Done
To find the total work done, we simply add the work done in the horizontal and vertical directions:
Total Work Done = Work in Horizontal Direction + Work in Vertical Direction
= 50 Joules + 0 Joules
= 50 Joules
Therefore, the total work done by the person is 50 Joules.
Community Answer
a person is holding a bucket by applying a force of 10 Newton. he move...
W=Force (F) x Distance (s)
w=10N x 10m
Ans= 100J
w=10N x 10m
Ans= 100J
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a person is holding a bucket by applying a force of 10 Newton. he moved a horizontal distance of 5 metre and then come climbs up a vertical distance of 10 metre. find the total work done by him.
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a person is holding a bucket by applying a force of 10 Newton. he moved a horizontal distance of 5 metre and then come climbs up a vertical distance of 10 metre. find the total work done by him. for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about a person is holding a bucket by applying a force of 10 Newton. he moved a horizontal distance of 5 metre and then come climbs up a vertical distance of 10 metre. find the total work done by him. covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for a person is holding a bucket by applying a force of 10 Newton. he moved a horizontal distance of 5 metre and then come climbs up a vertical distance of 10 metre. find the total work done by him..
a person is holding a bucket by applying a force of 10 Newton. he moved a horizontal distance of 5 metre and then come climbs up a vertical distance of 10 metre. find the total work done by him. for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about a person is holding a bucket by applying a force of 10 Newton. he moved a horizontal distance of 5 metre and then come climbs up a vertical distance of 10 metre. find the total work done by him. covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for a person is holding a bucket by applying a force of 10 Newton. he moved a horizontal distance of 5 metre and then come climbs up a vertical distance of 10 metre. find the total work done by him..
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