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If A+B+C=180 then cos 2A+cos 2B+cos 2C+1=
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If A+B+C=180 then cos 2A+cos 2B+cos 2C+1=
Explanation of cos 2A cos 2B cos 2C 1 when A B C=180



  • Introduction: In this question, we need to prove that cos 2A cos 2B cos 2C = 1 when A + B + C = 180 degrees.

  • Using Trigonometric Identities: We can start by using some trigonometric identities to express cos 2A, cos 2B, and cos 2C in terms of cos A, cos B, cos C, sin A, sin B, and sin C.

  • Using Double Angle Formulas: Then, we can use the double angle formulas for cosine to express cos 2A, cos 2B, and cos 2C in terms of cos A, cos B, cos C, and sin A, sin B, sin C.

  • Substituting Values: Next, we can substitute the value of A + B + C = 180 degrees into our expressions for cos 2A, cos 2B, and cos 2C. This will result in some terms canceling out.

  • Applying Identities: We can then apply some trigonometric identities to simplify the remaining terms. Specifically, we can use the identity sin A sin B sin C = sin (A + B + C) to simplify the product of sin A, sin B, and sin C.

  • Simplifying the Product: After simplifying the product of sin A, sin B, and sin C, we will be left with a product of cosines. This product will simplify to 1, which proves that cos 2A cos 2B cos 2C = 1 when A + B + C = 180 degrees.



Therefore, we can conclude that cos 2A cos 2B cos 2C = 1 when A + B + C = 180 degrees.
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If A+B+C=180 then cos 2A+cos 2B+cos 2C+1=
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If A+B+C=180 then cos 2A+cos 2B+cos 2C+1=
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