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A stone thrown at an angle θ to the horizontal reaches a maximum height h. The time of flight of the stone is
  • a)
    √2h sin θ/g
  • b)
    2√2h sin θ/g
  • c)
    2√2h/g
  • d)
    √2h/g
Correct answer is option 'C'. Can you explain this answer?
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A stone thrown at an angle θ to the horizontal reaches a maximum...
When a stone is thrown at an angle, it follows a curved path known as a projectile motion. The initial velocity of the stone is split into two components: horizontal and vertical. The horizontal component of the velocity remains constant throughout the motion, while the vertical component changes due to the effect of gravity.

As the stone moves forward, the force of gravity pulls it downward, causing it to fall towards the ground. The angle at which the stone is thrown determines the height and distance it will travel. If the angle is too high or too low, the stone may not reach its intended target.

The maximum range of a projectile is achieved when it is thrown at an angle of 45 degrees. At this angle, the horizontal and vertical components of the velocity are equal, resulting in the maximum range. However, in real-life situations, other factors such as air resistance and wind can affect the motion of the stone.
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A stone thrown at an angle θ to the horizontal reaches a maximum height h. The time of flight of the stone isa)√2h sin θ/gb)2√2h sin θ/gc)2√2h/gd)√2h/gCorrect answer is option 'C'. Can you explain this answer?
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