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The rms speed of gas molecules at a temperatre 27 K and pressure 1.5 bar is 1x104 cm/sec. If both temperature and pressure are raised three times, the rms speed of the gas will be: a)9 x 104 cm/sec b)3x104 cm/sec c)1x104 cm/sec d)=1 x 104 cm/secCorrect answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The rms speed of gas molecules at a temperatre 27 K and pressure 1.5 bar is 1x104 cm/sec. If both temperature and pressure are raised three times, the rms speed of the gas will be: a)9 x 104 cm/sec b)3x104 cm/sec c)1x104 cm/sec d)=1 x 104 cm/secCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The rms speed of gas molecules at a temperatre 27 K and pressure 1.5 bar is 1x104 cm/sec. If both temperature and pressure are raised three times, the rms speed of the gas will be: a)9 x 104 cm/sec b)3x104 cm/sec c)1x104 cm/sec d)=1 x 104 cm/secCorrect answer is option 'D'. Can you explain this answer?.

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