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Solid ammonium carbonate (NH2CO2NH4) dissociates completely into ammonia and carbon dioxide when it evaporates :

At 298 K, the total pressure of the gases in equilibrium with the solid is 0.116 atm. Derive the value of equilibrium constant Kp.
  • a)
    4p3/27
  • b)
    6p3/27
  • c)
    4p2/27
  • d)
    2p3/27
Correct answer is option 'A'. Can you explain this answer?
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Solid ammonium carbonate (NH2CO2NH4) dissociates completely into ammon...
A
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Solid ammonium carbonate (NH2CO2NH4) dissociates completely into ammonia and carbon dioxide when it evaporates :At 298 K, the total pressure of the gases in equilibrium with the solid is 0.116 atm. Derive the value of equilibrium constant Kp.a)4p3/27b)6p3/27c)4p2/27d)2p3/27Correct answer is option 'A'. Can you explain this answer?
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Solid ammonium carbonate (NH2CO2NH4) dissociates completely into ammonia and carbon dioxide when it evaporates :At 298 K, the total pressure of the gases in equilibrium with the solid is 0.116 atm. Derive the value of equilibrium constant Kp.a)4p3/27b)6p3/27c)4p2/27d)2p3/27Correct answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Solid ammonium carbonate (NH2CO2NH4) dissociates completely into ammonia and carbon dioxide when it evaporates :At 298 K, the total pressure of the gases in equilibrium with the solid is 0.116 atm. Derive the value of equilibrium constant Kp.a)4p3/27b)6p3/27c)4p2/27d)2p3/27Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Solid ammonium carbonate (NH2CO2NH4) dissociates completely into ammonia and carbon dioxide when it evaporates :At 298 K, the total pressure of the gases in equilibrium with the solid is 0.116 atm. Derive the value of equilibrium constant Kp.a)4p3/27b)6p3/27c)4p2/27d)2p3/27Correct answer is option 'A'. Can you explain this answer?.
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