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Calculate the total enthalpy change in melting 180g of ice at 0 degree celcius,heat it to 100 degrees and the vaporize it at that temperature. ∆fusH(ice)=6.01KJ/mol at 0 degrees , ∆vapH(H2O)=40.7KJ/mol at 100degrees.specific heat of water=4.18J/K/g? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Calculate the total enthalpy change in melting 180g of ice at 0 degree celcius,heat it to 100 degrees and the vaporize it at that temperature. ∆fusH(ice)=6.01KJ/mol at 0 degrees , ∆vapH(H2O)=40.7KJ/mol at 100degrees.specific heat of water=4.18J/K/g? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate the total enthalpy change in melting 180g of ice at 0 degree celcius,heat it to 100 degrees and the vaporize it at that temperature. ∆fusH(ice)=6.01KJ/mol at 0 degrees , ∆vapH(H2O)=40.7KJ/mol at 100degrees.specific heat of water=4.18J/K/g?.

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