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If x=1+√2 then find (x+1÷x)whole cube
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If x=1+√2 then find (x+1÷x)whole cube
Rationalize 1/x.
1/x
=1/(1+√2)
=(1-√2)/{(1+√2)(1-√2)}
=(1-√2)/(1² - √2²)
=(1-√2)/(1-2)
=(1-√2)/(-1)

therefore, x + 1/x = 1+√2 + (1-√2)/(-1)
= 1+√2-1+√2
=. 2√2

please do understand the process of rationalization if you do not know it.
it's very important
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