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If the current changes from 20A to 10A in 5 seconds and the value of inductance is 1H, calculate the emf induced.
- a)8V
- b)6V
- c)4V
- d)2V
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
If the current changes from 20A to 10A in 5 seconds and the value of i...
We know that:
emf=L(i2-i1)/t
Substituting the values from the question we get emf=2V.
emf=L(i2-i1)/t
Substituting the values from the question we get emf=2V.
Most Upvoted Answer
If the current changes from 20A to 10A in 5 seconds and the value of i...
**Given:**
- Initial current (I1) = 20A
- Final current (I2) = 10A
- Time taken (t) = 5 seconds
- Inductance (L) = 1H
**To find:**
The emf induced (ε)
**Formula:**
The emf induced in an inductor is given by the equation:
ε = -L * ΔI/Δt
where,
ε = emf induced
L = inductance
ΔI = change in current
Δt = change in time
**Calculation:**
Given that the initial current (I1) is 20A and the final current (I2) is 10A, we can find the change in current (ΔI) as:
ΔI = I2 - I1
ΔI = 10A - 20A
ΔI = -10A
Substituting the values into the formula:
ε = -L * ΔI/Δt
ε = -1H * (-10A)/5s
ε = -(-10A) * 1H/5s
ε = 10V/5s
ε = 2V
Therefore, the emf induced in the inductor is 2V.
- Initial current (I1) = 20A
- Final current (I2) = 10A
- Time taken (t) = 5 seconds
- Inductance (L) = 1H
**To find:**
The emf induced (ε)
**Formula:**
The emf induced in an inductor is given by the equation:
ε = -L * ΔI/Δt
where,
ε = emf induced
L = inductance
ΔI = change in current
Δt = change in time
**Calculation:**
Given that the initial current (I1) is 20A and the final current (I2) is 10A, we can find the change in current (ΔI) as:
ΔI = I2 - I1
ΔI = 10A - 20A
ΔI = -10A
Substituting the values into the formula:
ε = -L * ΔI/Δt
ε = -1H * (-10A)/5s
ε = -(-10A) * 1H/5s
ε = 10V/5s
ε = 2V
Therefore, the emf induced in the inductor is 2V.
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Question Description
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