Four successive members of the first row transition elements are listed below with their atomic no. Which of them is expected to have the highest third ionisation enthalpy?
  • a)
    iron (Z=26)
  • b)
    chromium(Z=24)
  • c)
    vanadium(Z=23)
  • d)
    manganese(Z=25)
Correct answer is option 'D'. Can you explain this answer?

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Answers

Shubham Rajput
May 09, 2019
Ionization energy is the amount of energy released when an electron is removed from a neutral or gaseous ion.

Atomic number of manganese is 25 and its electronic configuration is as follows.
1s²2s²2p63s²3p64s²3d5
     

So, when two electrons are removed then configuration of manganese becomes .
1s²2s²2p63s²3p64s03d5

Now, there are 5 electrons in 3d orbital and therefore, it is stable in nature due to half filled configuration of d orbital.

When another electron is removed then ionization energy will become exceptionally high because the 3d orbital is stable and thus high heat or energy has to be provided in order to remove an electron from it.

Anjali Pandey
Aug 08, 2021
In 

Third electron which is removed to give third

ionisation potential, belongs to 3d3 subshell.



Third electron which is removed to give third

ionisation potential, belongs to 3d5 subshell.



Third electron which is removed to give third

ionisation potential, belongs to 3d6 subshell.



Third electron which is removed to give third

ionisation potential, belongs to 3d5 subshell.

In all elements shell and subshells are same.

Required amount of energy (enthalpy) is based upon the stability of d-subshell.

The -subshell has high stability in all because it is half-filled subshell. So, Mn shows highest third ionisation potential.

Ionization energy is the amount of energy released when an electron is removed from a neutral or gaseous ion.Atomic number of manganese is 25 and its electronic configuration is as follows.1s²2s²2p63s²3p64s²3d5       So, when two electrons are removed then configuration of manganese becomes .1s²2s²2p63s²3p64s03d5Now, there are 5 electrons in 3d orbital and therefore, it is stable in nature due to half filled configuration of d orbital.When another electron is removed then ionization energy will become exceptionally high because the 3d orbital is stable and thus high heat or energy has to be provided in order to remove an electron from it.
Ionization energy is the amount of energy released when an electron is removed from a neutral or gaseous ion.Atomic number of manganese is 25 and its electronic configuration is as follows.1s²2s²2p63s²3p64s²3d5       So, when two electrons are removed then configuration of manganese becomes .1s²2s²2p63s²3p64s03d5Now, there are 5 electrons in 3d orbital and therefore, it is stable in nature due to half filled configuration of d orbital.When another electron is removed then ionization energy will become exceptionally high because the 3d orbital is stable and thus high heat or energy has to be provided in order to remove an electron from it.