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A coin is dropped in a lift . It takes time t1 to reach the floor when lift is stationary. It takes time t2 when lift is moving up with constant acceleration. Then A: t1 is greater than t2 B: t2 is greater than t1 C:t1= t2 D:t1 is much greater than t2?
Most Upvoted Answer
A coin is dropped in a lift . It takes time t1 to reach the floor when...
Answer
The correct option is B: t2 is greater than t1.
Explanation
When the lift is stationary, the only force acting on the coin is its weight. Therefore, it falls freely under the influence of gravity. The time taken by the coin to reach the floor is given by the equation:
t1 = sqrt(2h/g)
where h is the height of the lift and g is the acceleration due to gravity.
When the lift is moving up with constant acceleration, an additional force is acting on the coin - the upward force due to the lift's acceleration. This reduces the effective acceleration due to gravity experienced by the coin. Therefore, the coin falls slower and takes more time to reach the floor. The time taken by the coin to reach the floor is given by the equation:
t2 = sqrt(2(h + 0.5at^2)/g_eff)
where a is the acceleration of the lift, t is the time taken by the coin to reach the floor, and g_eff is the effective acceleration due to gravity experienced by the coin.
Since the effective acceleration due to gravity experienced by the coin is less than g, t2 > t1. Hence, the correct option is B: t2 is greater than t1.
Community Answer
A coin is dropped in a lift . It takes time t1 to reach the floor when...
The correct answer will be "t1 will be greater than t2" . When a coin is dropped in a lift which is stationary the acceleration acting on it is only acceleration due to gravity but when the same coin is dropped in a lift which is moving up with a constant acceleration the relative acceleration will be acceleration of lift plus the acceleration due to gravity (since they are in opposite direction). Due to this reason the coin will take less time to come down in the second case.
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A coin is dropped in a lift . It takes time t1 to reach the floor when lift is stationary. It takes time t2 when lift is moving up with constant acceleration. Then A: t1 is greater than t2 B: t2 is greater than t1 C:t1= t2 D:t1 is much greater than t2?
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A coin is dropped in a lift . It takes time t1 to reach the floor when lift is stationary. It takes time t2 when lift is moving up with constant acceleration. Then A: t1 is greater than t2 B: t2 is greater than t1 C:t1= t2 D:t1 is much greater than t2? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A coin is dropped in a lift . It takes time t1 to reach the floor when lift is stationary. It takes time t2 when lift is moving up with constant acceleration. Then A: t1 is greater than t2 B: t2 is greater than t1 C:t1= t2 D:t1 is much greater than t2? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A coin is dropped in a lift . It takes time t1 to reach the floor when lift is stationary. It takes time t2 when lift is moving up with constant acceleration. Then A: t1 is greater than t2 B: t2 is greater than t1 C:t1= t2 D:t1 is much greater than t2?.
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