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Two particles are projected simultaneously with the same speed v in the same vertical plane with angles of elevation θ and 2θ where θ < 45°. Their velocity becomes parallel at t= v/g f(θ/2) what will be
    Correct answer is '2'. Can you explain this answer?
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    Two particles are projected simultaneously with the same speed v in th...
    Velocity of I particle time t 

    Velocity of I particle after time t 

    To be parallel of V1 and V2 

     and θ = 30° (g = 10 m/s2)
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    Most Upvoted Answer
    Two particles are projected simultaneously with the same speed v in th...
    Of θ1 and θ2, respectively, with the horizontal. If θ1 < θ2,="" then="" the="" particle="" projected="" at="" angle="" θ1="" will="" reach="" a="" higher="" maximum="" than="" the="" particle="" projected="" at="" angle="" />

    This can be explained by considering the vertical component of the initial velocity of the particles. Since both particles are projected with the same speed v, the vertical component of the initial velocity of the particle projected at angle θ1 will be greater than the vertical component of the initial velocity of the particle projected at angle θ2. This means that the particle projected at angle θ1 will reach a higher maximum height before falling back down to the ground.

    In summary, the particle projected at a smaller angle of elevation will reach a higher maximum height compared to the particle projected at a larger angle of elevation, provided they are projected with the same initial speed.
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    Two particles are projected simultaneously with the same speed v in the same vertical plane with angles of elevationθ and 2θ whereθ < 45°.Their velocity becomes parallel at t= v/gf(θ/2) what will beCorrect answer is '2'. Can you explain this answer?
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