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A thief steals a car at 9 am and drive at the rate of 20 km/h. The theft is discovered and police starts chasing him at 9.30 am. in a jeep at the speed of 40 km/h. The thief will be caught at ………
- a)10 am
- b)10.30 am.
- c)11 am.
- d)None
- e)All of the above
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A thief steals a car at 9 am and drive at the rate of 20 km/h. The the...
The correct answer is A as
Relative speed = 40-20 (same distance)
Distance = 10 KM
Time = distance/time = 10/20 = 1/2 hours = 30 minutes
9.30 + 30 = 10 AM
Relative speed = 40-20 (same distance)
Distance = 10 KM
Time = distance/time = 10/20 = 1/2 hours = 30 minutes
9.30 + 30 = 10 AM
Most Upvoted Answer
A thief steals a car at 9 am and drive at the rate of 20 km/h. The the...
The problem involves a thief stealing a car and the police chasing after him. We are given the speeds at which both the thief and the police are driving. We need to determine at what time the thief will be caught.
Let's break down the problem step by step:
1. Time of theft: The thief steals the car at 9 am.
2. Time of chase: The police start chasing the thief at 9:30 am, which means there is a 30-minute time gap between the theft and the chase.
3. Speed of the thief: The thief is driving at a speed of 20 km/h.
4. Speed of the police: The police are driving a jeep at a speed of 40 km/h.
To determine at what time the thief will be caught, we need to calculate the distance traveled by both the thief and the police.
Distance traveled by the thief:
Since the thief steals the car at 9 am and the chase starts at 9:30 am, the thief has been driving for 30 minutes. Therefore, the distance traveled by the thief is:
Distance = Speed × Time
Distance = 20 km/h × 0.5 h (30 minutes converted to hours)
Distance = 10 km
Distance traveled by the police:
Since the police start chasing the thief at 9:30 am, they have been driving for a certain amount of time. Let's assume the time it takes for the police to catch the thief is t hours. Therefore, the distance traveled by the police is:
Distance = Speed × Time
Distance = 40 km/h × t
Now, since the thief and the police are traveling the same distance, we can set up an equation:
10 km = 40 km/h × t
Solving for t:
t = 10 km / 40 km/h
t = 0.25 h (15 minutes)
Therefore, it will take the police 15 minutes to catch the thief.
Adding the chase time to the time of chase start:
9:30 am + 0.25 h = 9:45 am
Therefore, the thief will be caught at 10 am (option A).
In conclusion, the correct answer is option A - 10 am.
Let's break down the problem step by step:
1. Time of theft: The thief steals the car at 9 am.
2. Time of chase: The police start chasing the thief at 9:30 am, which means there is a 30-minute time gap between the theft and the chase.
3. Speed of the thief: The thief is driving at a speed of 20 km/h.
4. Speed of the police: The police are driving a jeep at a speed of 40 km/h.
To determine at what time the thief will be caught, we need to calculate the distance traveled by both the thief and the police.
Distance traveled by the thief:
Since the thief steals the car at 9 am and the chase starts at 9:30 am, the thief has been driving for 30 minutes. Therefore, the distance traveled by the thief is:
Distance = Speed × Time
Distance = 20 km/h × 0.5 h (30 minutes converted to hours)
Distance = 10 km
Distance traveled by the police:
Since the police start chasing the thief at 9:30 am, they have been driving for a certain amount of time. Let's assume the time it takes for the police to catch the thief is t hours. Therefore, the distance traveled by the police is:
Distance = Speed × Time
Distance = 40 km/h × t
Now, since the thief and the police are traveling the same distance, we can set up an equation:
10 km = 40 km/h × t
Solving for t:
t = 10 km / 40 km/h
t = 0.25 h (15 minutes)
Therefore, it will take the police 15 minutes to catch the thief.
Adding the chase time to the time of chase start:
9:30 am + 0.25 h = 9:45 am
Therefore, the thief will be caught at 10 am (option A).
In conclusion, the correct answer is option A - 10 am.
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Community Answer
A thief steals a car at 9 am and drive at the rate of 20 km/h. The the...
When the thief started at 9 Am and drove for 30 minutes he covers a distance of 10 KM at a rate of 20 km/h (20 Km in 1 hour so 10 km in 30 minutes)
Now the policeman starts at 9.30 at the speed of 40 Km/h
Relative speed = 40-20 (same distance)
Distance = 10 KM
Time = distance/time = 10/20 = 1/2 hours = 30 minutes
9.30 + 30 = 10 AM
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Question Description
A thief steals a car at 9 am and drive at the rate of 20 km/h. The theft is discovered and police starts chasing him at 9.30 am. in a jeep at the speed of 40 km/h. The thief will be caught at ………a)10 amb)10.30 am.c)11 am.d)Nonee)All of the aboveCorrect answer is option 'A'. Can you explain this answer? for Quant 2026 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about A thief steals a car at 9 am and drive at the rate of 20 km/h. The theft is discovered and police starts chasing him at 9.30 am. in a jeep at the speed of 40 km/h. The thief will be caught at ………a)10 amb)10.30 am.c)11 am.d)Nonee)All of the aboveCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Quant 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A thief steals a car at 9 am and drive at the rate of 20 km/h. The theft is discovered and police starts chasing him at 9.30 am. in a jeep at the speed of 40 km/h. The thief will be caught at ………a)10 amb)10.30 am.c)11 am.d)Nonee)All of the aboveCorrect answer is option 'A'. Can you explain this answer?.
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