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A parallel beam of uniform monochromatic light of wavelength 2640 a has an intensity of 200w/m^2.the number of photons in 1 mm^3 of this radiation are____?
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A parallel beam of uniform monochromatic light of wavelength 2640 a ha...
Answer = 885
Intensity = power / area
given:
Area= 1× 10^-6 m^2
Intensity = 200 W m^-2
wavelength of photon = 2640 A•
energy of One photon = hc/wavelength of photon = 7.5×10^-19J
time = distance/velocity = 10^-3m/c
N = Intensity × area × time / energy of one photon
Intensity = power / area
given:
Area= 1× 10^-6 m^2
Intensity = 200 W m^-2
wavelength of photon = 2640 A•
energy of One photon = hc/wavelength of photon = 7.5×10^-19J
time = distance/velocity = 10^-3m/c
N = Intensity × area × time / energy of one photon
Community Answer
A parallel beam of uniform monochromatic light of wavelength 2640 a ha...
Calculating the Number of Photons in 1 mm^3 of Radiation
1. Given Data:
- Wavelength of light (λ) = 2640 angstroms = 2640 x 10^-10 meters
- Intensity of light (I) = 200 W/m^2
- Speed of light (c) = 3 x 10^8 m/s
- Planck's constant (h) = 6.63 x 10^-34 J*s
2. Calculating Energy of a Single Photon:
- Energy of a photon (E) can be calculated using the formula E = hc/λ, where h is Planck's constant and c is the speed of light.
- Substituting the values: E = (6.63 x 10^-34 J*s x 3 x 10^8 m/s) / (2640 x 10^-10 m)
- E = 7.52 x 10^-19 Joules
3. Calculating Number of Photons:
- Intensity (I) is the energy passing through a unit area in a unit time.
- Number of photons passing through an area in a unit time can be calculated using the formula:
Number of photons = Intensity / Energy of a single photon
- Substituting the values: Number of photons = 200 / 7.52 x 10^-19
- Number of photons = 2.65 x 10^20 photons/m^2
- To find the number of photons in 1 mm^3, we need to consider the volume.
- 1 mm^3 = 1 x 10^-9 m^3
- Number of photons in 1 mm^3 = (2.65 x 10^20) x (1 x 10^-9)
- Number of photons in 1 mm^3 = 2.65 x 10^11 photons
Therefore, the number of photons in 1 mm^3 of this radiation is approximately 2.65 x 10^11 photons.
1. Given Data:
- Wavelength of light (λ) = 2640 angstroms = 2640 x 10^-10 meters
- Intensity of light (I) = 200 W/m^2
- Speed of light (c) = 3 x 10^8 m/s
- Planck's constant (h) = 6.63 x 10^-34 J*s
2. Calculating Energy of a Single Photon:
- Energy of a photon (E) can be calculated using the formula E = hc/λ, where h is Planck's constant and c is the speed of light.
- Substituting the values: E = (6.63 x 10^-34 J*s x 3 x 10^8 m/s) / (2640 x 10^-10 m)
- E = 7.52 x 10^-19 Joules
3. Calculating Number of Photons:
- Intensity (I) is the energy passing through a unit area in a unit time.
- Number of photons passing through an area in a unit time can be calculated using the formula:
Number of photons = Intensity / Energy of a single photon
- Substituting the values: Number of photons = 200 / 7.52 x 10^-19
- Number of photons = 2.65 x 10^20 photons/m^2
- To find the number of photons in 1 mm^3, we need to consider the volume.
- 1 mm^3 = 1 x 10^-9 m^3
- Number of photons in 1 mm^3 = (2.65 x 10^20) x (1 x 10^-9)
- Number of photons in 1 mm^3 = 2.65 x 10^11 photons
Therefore, the number of photons in 1 mm^3 of this radiation is approximately 2.65 x 10^11 photons.
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A parallel beam of uniform monochromatic light of wavelength 2640 a has an intensity of 200w/m^2.the number of photons in 1 mm^3 of this radiation are____?
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A parallel beam of uniform monochromatic light of wavelength 2640 a has an intensity of 200w/m^2.the number of photons in 1 mm^3 of this radiation are____? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A parallel beam of uniform monochromatic light of wavelength 2640 a has an intensity of 200w/m^2.the number of photons in 1 mm^3 of this radiation are____? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A parallel beam of uniform monochromatic light of wavelength 2640 a has an intensity of 200w/m^2.the number of photons in 1 mm^3 of this radiation are____?.
A parallel beam of uniform monochromatic light of wavelength 2640 a has an intensity of 200w/m^2.the number of photons in 1 mm^3 of this radiation are____? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A parallel beam of uniform monochromatic light of wavelength 2640 a has an intensity of 200w/m^2.the number of photons in 1 mm^3 of this radiation are____? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A parallel beam of uniform monochromatic light of wavelength 2640 a has an intensity of 200w/m^2.the number of photons in 1 mm^3 of this radiation are____?.
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