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Two points are located at a distance of 10 m and 15 m from the source of oscillation . The period of oscillation is 0.05 sec and the velocity of the wave is 300 m/sec. What is the phase difference between the oscillations of two points ?
  • a)
    π/6
  • b)
    π/3
  • c)
    2π/ 3
  • d)
    π
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Two points are located at a distance of 10 m and 15 m from the source ...
∆x=15-10=5
v= 2π/Tk
300=2π/Tk
put T=0.05 you will get k= 2π/15
k=2π/wavelength
put value of k you will get, wavelength= 15
now phase difference =2π×∆x/wavelength
put ∆x and wavelength value found earlier you will get phase difference = 2π/3
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Two points are located at a distance of 10 m and 15 m from the source of oscillation . The period of oscillation is 0.05 sec and the velocity of the wave is 300 m/sec. What is the phase difference between the oscillations of two points ?a)π/6b)π/3c)2π/3d)πCorrect answer is option 'C'. Can you explain this answer?
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