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Range of f(x) = sin–1 x + tan–1 x + sec–1 x is
  • a)
  • b)
  • c)
  • d)
    None of these
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Range of f(x) = sin–1x + tan–1x + sec–1x isa)b)c)d)N...
The function f is defined for x = ±1 
Now, f(1) = sin-1(1) + sec-1(1) + tan-1(1) 
= π/2 + 0 + π/4 = 3π/4 
Also, f(-1) = sin-1(-1) + sec-1(-1) + tan-1(-1) 
= - π/2 + π - 0 - π/4 
= 3π/4
Range = { π/4, 3π/4}
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Most Upvoted Answer
Range of f(x) = sin–1x + tan–1x + sec–1x isa)b)c)d)N...
The function f is defined for x = ±1 
Now, f(1) = sin-1(1) + sec-1(1) + tan-1(1) 
= π/2 + 0 + π/4 = 3π/4 
Also, f(-1) = sin-1(-1) + sec-1(-1) + tan-1(-1) 
= - π/2 + π - 0 - π/4 
= 3π/4
Range = { π/4, 3π/4}
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Community Answer
Range of f(x) = sin–1x + tan–1x + sec–1x isa)b)c)d)N...
From domain of sin-x & sec-x we get only two values of x=1&-1
so now for x=1 y=3π/4
x=-1 y=π/4
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Range of f(x) = sin–1x + tan–1x + sec–1x isa)b)c)d)None of theseCorrect answer is option 'C'. Can you explain this answer? for JEE 2026 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Range of f(x) = sin–1x + tan–1x + sec–1x isa)b)c)d)None of theseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Range of f(x) = sin–1x + tan–1x + sec–1x isa)b)c)d)None of theseCorrect answer is option 'C'. Can you explain this answer?.
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