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solve 0.47bar maths exercise 1.3
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solve 0.47bar maths exercise 1.3
Solving 0.47bar Maths Exercise 1.3
Understanding the Problem
The problem requires us to solve 0.47bar. This notation means that the decimal value 0.47 repeats indefinitely. The bar above the digits indicates that they repeat infinitely.
Converting to Fraction
To convert 0.47bar to a fraction, we can use the following steps:
- Let x = 0.47bar
- Multiply both sides by 100 to remove the decimal point: 100x = 47.bar
- Subtract x from 100x: 100x - x = 47.bar - 0.47bar
- Simplify: 99x = 47
- Divide both sides by 99: x = 47/99
Therefore, 0.47bar is equivalent to the fraction 47/99.
Checking for Simplification
To check if 47/99 can be simplified, we can find the greatest common factor (GCF) of the numerator and denominator.
- The prime factors of 47 are 1 and 47.
- The prime factors of 99 are 1, 3, 9, 11, 33, and 99.
The only common factor is 1, so 47/99 cannot be simplified any further.
Final Answer
Therefore, the solution to 0.47bar is the fraction 47/99, which cannot be simplified any further.
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solve 0.47bar maths exercise 1.3
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solve 0.47bar maths exercise 1.3 for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about solve 0.47bar maths exercise 1.3 covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for solve 0.47bar maths exercise 1.3 .
solve 0.47bar maths exercise 1.3 for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about solve 0.47bar maths exercise 1.3 covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for solve 0.47bar maths exercise 1.3 .
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