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the momentum of a body is increased by 25%the kinetic energy is increased by about
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Explanation of the Increase in Momentum and Kinetic Energy of a Body
What is Momentum?
Momentum is the product of the mass and velocity of a body. It is a vector quantity and is measured in kilogram-meters per second (kg m/s).
What is Kinetic Energy?
Kinetic energy is the energy possessed by a body due to its motion. It is directly proportional to the mass and the square of the velocity of the body.
How is the Momentum of a Body Increased by 25%?
The momentum of a body can be increased by increasing its mass or velocity. If the mass of the body remains constant, then the momentum can be increased by increasing its velocity.
If the momentum of a body is increased by 25%, then the new momentum will be 1.25 times the original momentum.
How is the Kinetic Energy of a Body Increased by About 56.25%?
The kinetic energy of a body is directly proportional to the square of its velocity. Therefore, if the velocity of a body is increased by 25%, then its kinetic energy will increase by approximately 56.25%.
The increase in kinetic energy can be calculated as:
New Kinetic Energy = 1/2 x m x (1.25v)^2
where m is the mass of the body and v is its original velocity.
Substituting the values, we get:
New Kinetic Energy = 1/2 x m x 1.5625v^2
Therefore, the new kinetic energy is approximately 56.25% higher than the original kinetic energy.
Conclusion
Thus, the momentum and kinetic energy of a body can be increased by increasing its velocity. If the momentum is increased by 25%, then the kinetic energy will increase by approximately 56.25%.
Community Answer
the momentum of a body is increased by 25%the kinetic energy is increa...
Let initial momentum be p where
p=m×v
and KE=1/2mv^2
={(mv)^2}/2m
=p^2/2m
when momentum is increased by 25%
p=1.25p
so KE=(1.25p)^2/2m
percentage increase in KE =
[{(1.25p)^2/2m}-p^2/2m]p^2/2m×100
=56.25%
p=m×v
and KE=1/2mv^2
={(mv)^2}/2m
=p^2/2m
when momentum is increased by 25%
p=1.25p
so KE=(1.25p)^2/2m
percentage increase in KE =
[{(1.25p)^2/2m}-p^2/2m]p^2/2m×100
=56.25%
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the momentum of a body is increased by 25%the kinetic energy is increased by about for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about the momentum of a body is increased by 25%the kinetic energy is increased by about covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for the momentum of a body is increased by 25%the kinetic energy is increased by about .
the momentum of a body is increased by 25%the kinetic energy is increased by about for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about the momentum of a body is increased by 25%the kinetic energy is increased by about covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for the momentum of a body is increased by 25%the kinetic energy is increased by about .
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