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Passage IAn alkane (A) molecular formula C6H14 reacts with chlorine in the presence of ultraviolet light to yield three positional isomers as monochloro derivatives (B), (C)and (D). Of these, only (C) and (D) undergo dehydrohalogenation with sodium ethoxide in ethanol to produce an alkene. Moreover, (C) and (D) yields the same alkene (E) (C6H12). Hydrogenation of (E) produces (A). Treating (E)with HCI produces a compound (F) that is an isomer of (B), (C) and (D). Treating (F) with Zn and acetic acid gives a compound (G), which is isomeric with (A).Q.The compound G reacts with chlorine in the presence of ultraviolet light to yield how many isomers as monochloro derivatives?a)1b)2c)3d)4Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Passage IAn alkane (A) molecular formula C6H14 reacts with chlorine in the presence of ultraviolet light to yield three positional isomers as monochloro derivatives (B), (C)and (D). Of these, only (C) and (D) undergo dehydrohalogenation with sodium ethoxide in ethanol to produce an alkene. Moreover, (C) and (D) yields the same alkene (E) (C6H12). Hydrogenation of (E) produces (A). Treating (E)with HCI produces a compound (F) that is an isomer of (B), (C) and (D). Treating (F) with Zn and acetic acid gives a compound (G), which is isomeric with (A).Q.The compound G reacts with chlorine in the presence of ultraviolet light to yield how many isomers as monochloro derivatives?a)1b)2c)3d)4Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Passage IAn alkane (A) molecular formula C6H14 reacts with chlorine in the presence of ultraviolet light to yield three positional isomers as monochloro derivatives (B), (C)and (D). Of these, only (C) and (D) undergo dehydrohalogenation with sodium ethoxide in ethanol to produce an alkene. Moreover, (C) and (D) yields the same alkene (E) (C6H12). Hydrogenation of (E) produces (A). Treating (E)with HCI produces a compound (F) that is an isomer of (B), (C) and (D). Treating (F) with Zn and acetic acid gives a compound (G), which is isomeric with (A).Q.The compound G reacts with chlorine in the presence of ultraviolet light to yield how many isomers as monochloro derivatives?a)1b)2c)3d)4Correct answer is option 'C'. Can you explain this answer?.

Solutions for Passage IAn alkane (A) molecular formula C6H14 reacts with chlorine in the presence of ultraviolet light to yield three positional isomers as monochloro derivatives (B), (C)and (D). Of these, only (C) and (D) undergo dehydrohalogenation with sodium ethoxide in ethanol to produce an alkene. Moreover, (C) and (D) yields the same alkene (E) (C6H12). Hydrogenation of (E) produces (A). Treating (E)with HCI produces a compound (F) that is an isomer of (B), (C) and (D). Treating (F) with Zn and acetic acid gives a compound (G), which is isomeric with (A).Q.The compound G reacts with chlorine in the presence of ultraviolet light to yield how many isomers as monochloro derivatives?a)1b)2c)3d)4Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of Passage IAn alkane (A) molecular formula C6H14 reacts with chlorine in the presence of ultraviolet light to yield three positional isomers as monochloro derivatives (B), (C)and (D). Of these, only (C) and (D) undergo dehydrohalogenation with sodium ethoxide in ethanol to produce an alkene. Moreover, (C) and (D) yields the same alkene (E) (C6H12). Hydrogenation of (E) produces (A). Treating (E)with HCI produces a compound (F) that is an isomer of (B), (C) and (D). Treating (F) with Zn and acetic acid gives a compound (G), which is isomeric with (A).Q.The compound G reacts with chlorine in the presence of ultraviolet light to yield how many isomers as monochloro derivatives?a)1b)2c)3d)4Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Passage IAn alkane (A) molecular formula C6H14 reacts with chlorine in the presence of ultraviolet light to yield three positional isomers as monochloro derivatives (B), (C)and (D). Of these, only (C) and (D) undergo dehydrohalogenation with sodium ethoxide in ethanol to produce an alkene. Moreover, (C) and (D) yields the same alkene (E) (C6H12). Hydrogenation of (E) produces (A). Treating (E)with HCI produces a compound (F) that is an isomer of (B), (C) and (D). Treating (F) with Zn and acetic acid gives a compound (G), which is isomeric with (A).Q.The compound G reacts with chlorine in the presence of ultraviolet light to yield how many isomers as monochloro derivatives?a)1b)2c)3d)4Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Passage IAn alkane (A) molecular formula C6H14 reacts with chlorine in the presence of ultraviolet light to yield three positional isomers as monochloro derivatives (B), (C)and (D). Of these, only (C) and (D) undergo dehydrohalogenation with sodium ethoxide in ethanol to produce an alkene. Moreover, (C) and (D) yields the same alkene (E) (C6H12). Hydrogenation of (E) produces (A). Treating (E)with HCI produces a compound (F) that is an isomer of (B), (C) and (D). Treating (F) with Zn and acetic acid gives a compound (G), which is isomeric with (A).Q.The compound G reacts with chlorine in the presence of ultraviolet light to yield how many isomers as monochloro derivatives?a)1b)2c)3d)4Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Passage IAn alkane (A) molecular formula C6H14 reacts with chlorine in the presence of ultraviolet light to yield three positional isomers as monochloro derivatives (B), (C)and (D). Of these, only (C) and (D) undergo dehydrohalogenation with sodium ethoxide in ethanol to produce an alkene. Moreover, (C) and (D) yields the same alkene (E) (C6H12). Hydrogenation of (E) produces (A). Treating (E)with HCI produces a compound (F) that is an isomer of (B), (C) and (D). Treating (F) with Zn and acetic acid gives a compound (G), which is isomeric with (A).Q.The compound G reacts with chlorine in the presence of ultraviolet light to yield how many isomers as monochloro derivatives?a)1b)2c)3d)4Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Passage IAn alkane (A) molecular formula C6H14 reacts with chlorine in the presence of ultraviolet light to yield three positional isomers as monochloro derivatives (B), (C)and (D). Of these, only (C) and (D) undergo dehydrohalogenation with sodium ethoxide in ethanol to produce an alkene. Moreover, (C) and (D) yields the same alkene (E) (C6H12). Hydrogenation of (E) produces (A). Treating (E)with HCI produces a compound (F) that is an isomer of (B), (C) and (D). Treating (F) with Zn and acetic acid gives a compound (G), which is isomeric with (A).Q.The compound G reacts with chlorine in the presence of ultraviolet light to yield how many isomers as monochloro derivatives?a)1b)2c)3d)4Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.