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Q- lim x tends to infinity 100[{(x 1)(x 2)(x 3).(x 100)}to the power 1/100 -x] equals to ??? Ans- 5050?
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Q- lim x tends to infinity 100[{(x 1)(x 2)(x 3).(x 100)}to the power 1...
To find the value of the given limit, we can first rewrite the expression inside the brackets as a product of 100 factors:
100[{(x 1)(x 2)(x 3)....(x 100)}^(1/100) - x]

Next, we can use the fact that x^(1/n) = nth root of x to rewrite the expression inside the brackets as follows:

100[{(x^1)(x^2)(x^3)....(x^100)}^(1/100) - x]

Since the base of the exponent is the same for all 100 factors, we can rewrite the expression inside the brackets as follows:

100[x^(1+2+3+...+100)/100 - x]

Using the formula for the sum of an arithmetic series, we can rewrite the exponent as follows:

100[x^(5050/100) - x]

Simplifying the exponent gives us:

100[x^50.5 - x]

As x approaches infinity, the value of x^50.5 becomes much larger than the value of x, so the expression inside the brackets approaches positive infinity.

Since the expression is multiplied by 100, the overall value of the limit also approaches positive infinity as x approaches infinity.

Therefore, the answer to the given limit is positive infinity.

The answer 5050 is incorrect.

This question is part of UPSC exam. View all JEE courses
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Q- lim x tends to infinity 100[{(x 1)(x 2)(x 3).(x 100)}to the power 1...
Given:
We are given the limit as x approaches infinity of the expression:

lim(x -> ∞) 100[{(x+1)(x+2)(x+3)...(x+100)}^(1/100) - x]

Let's solve this limit step by step.

Step 1: Expanding the expression
We can expand the expression inside the curly brackets using the formula for the product of consecutive terms:

(x+1)(x+2)(x+3)...(x+100)

This can be written as:

x^100 + (1+2+3+...+100)x^99 + (1+2+3+...+100)(1+2+3+...+100)x^98 + ...

Simplifying further, we get:

x^100 + (1+2+3+...+100)x^99 + (1+2+3+...+100)^2x^98 + ...

Step 2: Simplifying the expression
We can see that as x approaches infinity, the terms with lower powers of x become insignificant compared to the highest power term (x^100). Therefore, we can ignore all the terms except for x^100.

Now, let's focus only on the x^100 term:

lim(x -> ∞) 100(x^100 - x)

Step 3: Simplifying the limit
We can factor out x from the expression inside the limit:

lim(x -> ∞) 100x(x^99 - 1)

As x approaches infinity, x^99 becomes much larger than 1. Therefore, we can ignore the -1 term compared to x^99.

Now, the expression becomes:

lim(x -> ∞) 100x(x^99)

Step 4: Evaluating the limit
As x approaches infinity, the term x^99 also approaches infinity. Therefore, we can rewrite the limit as:

∞ * ∞ * ∞ = ∞

So, the answer to the given limit is infinity, not 5050.

Note: The given answer of 5050 does not seem to be correct based on the provided expression and limit.
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Q- lim x tends to infinity 100[{(x 1)(x 2)(x 3).(x 100)}to the power 1/100 -x] equals to ??? Ans- 5050?
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