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Integrate - rootx(x^3/2-7x^5/2 9x^7/2)dx?
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Integrate - rootx(x^3/2-7x^5/2 9x^7/2)dx?
Integration of √x(x3/2-7x5/2+9x7/2)dx

To solve this integration problem, we can use the power rule of integration and substitution method.

Step 1: Simplify the expression

We can simplify the expression inside the square root by factoring out x3/2:

√x(x3/2-7x5/2+9x7/2)dx = √x(x3/2(1-7x+9x2))dx

Step 2: Substitute a new variable

Let's substitute u = 1-7x+9x2 and solve for x:

u = 1-7x+9x2

9x2-7x+(1-u) = 0

Using the quadratic formula, we get:

x = (7 ± √(49-36(1-u)))/18

x = (7 ± 5√u)/18

dx = (5/18) √u du

Step 3: Substitute u and simplify

Now, we can substitute u and dx in the integral expression:

∫ √x(x3/2-7x5/2+9x7/2)dx = ∫ √x(x3/2(1-7x+9x2))dx

= ∫ √x(x3/2u)dx

= ∫ x3/4u1/2(5/18) √u du

= (5/18) ∫ u1/2x3/4du

= (5/18) ∫ (1-7x+9x2)1/2x3/4du

This integral expression cannot be simplified further using elementary functions. Therefore, the final answer is:

∫ √x(x3/2-7x5/2+9x7/2)dx = (5/18) ∫ (1-7x+9x2)1/2x3/4du
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Integrate - rootx(x^3/2-7x^5/2 9x^7/2)dx?
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