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Two batteries of emf's 6.20 V and 12.45 volt and internal resistance 0.01ohm and 0.03 ohm respectively are being charged by a battery charger which supplies a current of 20 ampere.what are the terminal potential differences of the batteries during charging.?
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Two batteries of emf's 6.20 V and 12.45 volt and internal resistance 0...
Terminal Potential Differences during Charging
Calculating Terminal Potential Difference
The terminal potential difference of a battery can be calculated using the formula:
Vt = emf - Ir
Where Vt is the terminal potential difference, emf is the electromotive force, I is the current, and r is the internal resistance.
Calculating Current
Since the battery charger supplies a current of 20 amperes, the current flowing through each battery will also be 20 amperes.
Calculating Terminal Potential Difference for 6.20 V Battery
Using the formula above, we can calculate the terminal potential difference for the 6.20 V battery:
Vt = 6.20 - (20 x 0.01)
Vt = 5.20 V
Therefore, the terminal potential difference for the 6.20 V battery during charging is 5.20 V.
Calculating Terminal Potential Difference for 12.45 V Battery
Using the same formula, we can calculate the terminal potential difference for the 12.45 V battery:
Vt = 12.45 - (20 x 0.03)
Vt = 11.85 V
Therefore, the terminal potential difference for the 12.45 V battery during charging is 11.85 V.
Explanation
During charging, the battery charger supplies a current which flows through the batteries. As the current flows through the batteries, it encounters resistance due to the internal resistance of the batteries. This resistance causes a voltage drop, which reduces the terminal potential difference of the batteries.
The formula for calculating the terminal potential difference takes into account both the electromotive force of the battery and the voltage drop due to the internal resistance. By subtracting the product of the current and the internal resistance from the electromotive force, we can determine the terminal potential difference of the battery during charging.
In this case, the terminal potential difference for both batteries is reduced due to the current flowing through them and the resistance of their internal components. However, the larger battery with a higher emf and internal resistance has a higher terminal potential difference after accounting for the voltage drop.
Community Answer
Two batteries of emf's 6.20 V and 12.45 volt and internal resistance 0...
£=I(R+r)
as the emf is connected in series ,the total emf is the sum of the emfs
£=£1+£2=6.20V+ 12.45V=18.5V
the equivalent resistance in series is the sum of the internal resistances.
r=r1+r2=0.01ohm+0.03ohm=0.04ohm
In series connection the current is the same through out the circuit.
£=I(R+r)
18.5V=20A(R+(0.04ohm))
18.5V-20A(0.04ohm)=20A(R)
18.5V-0.8V=20R
17.7V=20R, R=0.885ohm
the terminal potential difference=IR
Vt=(20A)(0.885ohm)
Vt=17.7V ~ 18V
£1=I(R1+r1)
6.20V=20A(R1+0.01), R1=0.3ohm
Vterminal1=IR
=20A×0.3ohm=6V
£2=I(R2+r2)
12.45V=20A(R2+0.03ohm)
R2=0.59ohm
Vterminal2=IR
=20A(0.59ohm)=11.85V~12V
as the emf is connected in series ,the total emf is the sum of the emfs
£=£1+£2=6.20V+ 12.45V=18.5V
the equivalent resistance in series is the sum of the internal resistances.
r=r1+r2=0.01ohm+0.03ohm=0.04ohm
In series connection the current is the same through out the circuit.
£=I(R+r)
18.5V=20A(R+(0.04ohm))
18.5V-20A(0.04ohm)=20A(R)
18.5V-0.8V=20R
17.7V=20R, R=0.885ohm
the terminal potential difference=IR
Vt=(20A)(0.885ohm)
Vt=17.7V ~ 18V
£1=I(R1+r1)
6.20V=20A(R1+0.01), R1=0.3ohm
Vterminal1=IR
=20A×0.3ohm=6V
£2=I(R2+r2)
12.45V=20A(R2+0.03ohm)
R2=0.59ohm
Vterminal2=IR
=20A(0.59ohm)=11.85V~12V
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Two batteries of emf's 6.20 V and 12.45 volt and internal resistance 0.01ohm and 0.03 ohm respectively are being charged by a battery charger which supplies a current of 20 ampere.what are the terminal potential differences of the batteries during charging.?
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Two batteries of emf's 6.20 V and 12.45 volt and internal resistance 0.01ohm and 0.03 ohm respectively are being charged by a battery charger which supplies a current of 20 ampere.what are the terminal potential differences of the batteries during charging.? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Two batteries of emf's 6.20 V and 12.45 volt and internal resistance 0.01ohm and 0.03 ohm respectively are being charged by a battery charger which supplies a current of 20 ampere.what are the terminal potential differences of the batteries during charging.? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two batteries of emf's 6.20 V and 12.45 volt and internal resistance 0.01ohm and 0.03 ohm respectively are being charged by a battery charger which supplies a current of 20 ampere.what are the terminal potential differences of the batteries during charging.?.
Two batteries of emf's 6.20 V and 12.45 volt and internal resistance 0.01ohm and 0.03 ohm respectively are being charged by a battery charger which supplies a current of 20 ampere.what are the terminal potential differences of the batteries during charging.? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Two batteries of emf's 6.20 V and 12.45 volt and internal resistance 0.01ohm and 0.03 ohm respectively are being charged by a battery charger which supplies a current of 20 ampere.what are the terminal potential differences of the batteries during charging.? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two batteries of emf's 6.20 V and 12.45 volt and internal resistance 0.01ohm and 0.03 ohm respectively are being charged by a battery charger which supplies a current of 20 ampere.what are the terminal potential differences of the batteries during charging.?.
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