When H₂ and I₂ are mixed and equilibrium is attained, thena)amount of ...
Explanation:
The reaction between hydrogen gas (H₂) and iodine gas (I₂) to form hydrogen iodide gas (HI) is given as follows:
H₂(g) + I₂(g) ⇌ 2HI(g)
When H₂ and I₂ are mixed and equilibrium is attained, the following observations can be made:
- Amount of HI formed is NOT equal to the amount of H₂ dissociated: This is because the reaction involves both the forward and reverse reactions. The amounts of H₂, I₂, and HI present at equilibrium depend on the relative rates of the forward and reverse reactions, which in turn depend on various factors such as temperature, pressure, and concentrations of reactants and products. Therefore, the amount of HI formed is determined by the position of equilibrium, which can be shifted by changing the conditions of the reaction.
- HI dissociation does NOT stop: At equilibrium, some of the HI molecules will dissociate into H₂ and I₂, and some of the H₂ and I₂ molecules will react to form more HI. The rate of HI dissociation is equal to the rate of HI formation in the reverse reaction, as dictated by the equilibrium constant (Kc). Therefore, HI dissociation does not stop at equilibrium, but rather reaches a dynamic balance with HI formation.
- The reaction does NOT stop completely: As explained above, the reaction between H₂ and I₂ to form HI reaches an equilibrium state, where the rates of the forward and reverse reactions are equal. At this point, the reaction does not stop completely, but rather proceeds in both directions at the same rate. However, the net reaction rate is zero, since the amounts of reactants and products do not change over time.
Therefore, the correct answer is option D, "None of these".
When H₂ and I₂ are mixed and equilibrium is attained, thena)amount of ...
Ya equilibrium is not static it is dynamic equilibrium mean rate of dissociation of HI and rate of formation of HI is same
for more discussion go to reply section
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