A bus running at a speed of 18 km/h is stopped in 2.5 s by applying breaks. Calculate the retardation and the distance travelled before stopping?

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A bus running at a speed of 18 km/h is stopped in 2.5 s by applying breaks. Calculate the retardation and the distance travelled before stopping?

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A bus running at a speed of 18 km/h is stopped in 2.5 s by applying br...

Initial velocity = 18 km/h = 18 * 5/18 m/sec

= 5 m/sec

= [ km/h = 5/18 m/sec ]

= final velocity = zero

= acceleration = change in velocity/time

= ( final velocity - intial velocity)/time

= ( 0 - 5)/2.5 = -2 m/s^2

so, retardation = 2m/s^2

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