**Acceleration Calculation:**

To find the acceleration of the car, we can use the equation:

\[v = u + at\]

Where:
- \(v\) is the final velocity (72 km/h)
- \(u\) is the initial velocity (0 km/h, as the car starts from rest)
- \(a\) is the acceleration (unknown)
- \(t\) is the time taken (10 s)

Rearranging the equation, we get:

\[a = \frac{{v - u}}{{t}}\]

Substituting the given values, we have:

\[a = \frac{{72 - 0}}{{10}}\]
\[a = 7.2 \, \text{m/s}^2\]

Therefore, the acceleration of the car is \(7.2 \, \text{m/s}^2\).

**Distance Calculation:**

To find the distance traveled by the car, we can use the equation:

\[s = ut + \frac{1}{2}at^2\]

Where:
- \(s\) is the distance (unknown)
- \(u\) is the initial velocity (0 km/h)
- \(a\) is the acceleration (7.2 m/s²)
- \(t\) is the time taken (10 s)

Substituting the given values, we have:

\[s = 0 \times 10 + \frac{1}{2} \times 7.2 \times (10)^2\]
\[s = 0 + 0.5 \times 7.2 \times 100\]
\[s = 360 \, \text{m}\]

Therefore, the car has traveled a distance of 360 meters in 10 seconds.

**Summary:**

- The acceleration of the car is 7.2 m/s².
- The car has traveled a distance of 360 meters in 10 seconds.

Given,