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Find f(x)if y=x^3(2x^2-1)?
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Find f(x)if y=x^3(2x^2-1)?
Finding f(x) for y=x^3(2x^2-1)


Step 1: Expand the equation

First, we need to expand the equation y=x^3(2x^2-1) to get a clearer understanding of the function.

Expanding the equation gives:

y=2x^5-x^3


Step 2: Replace y with f(x)

We can replace y with f(x) to get the function in terms of x.

Therefore, f(x) = 2x^5 - x^3


Step 3: Simplify the function

We can simplify the function by factoring out x^3.

f(x) = x^3(2x^2 - 1)


Final Function

Therefore, the final function is:

f(x) = x^3(2x^2 - 1)


Explanation

The given equation, y=x^3(2x^2-1), can be expanded and simplified to get the function in terms of x, which is f(x) = x^3(2x^2 - 1).

The function is a polynomial function of degree 5, which means that it has 5 terms and the highest power of x is 5.

The function can be graphed to show the behavior of the function for different values of x. The graph will show that the function has one local maximum and one local minimum.

Therefore, the function f(x) can be used to model different real-life situations such as population growth, financial investments, and physical phenomena.
Community Answer
Find f(x)if y=x^3(2x^2-1)?
Here 
y = x^3(2x^2-1)
but f(x)= y
hence,
f(x) = x^3(2x^2-1)

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