Calculation of Equivalent Weight of M

Given Data:
- Mass of M2CO3 = 5.3 g
- Volume of HCl = 150 ml
- Concentration of HCl = 1 N
- Volume of NaOH = 100 ml
- Concentration of NaOH = 0.5 N

Step 1: Calculation of moles of HCl used
- We know that the concentration of HCl is 1 N, which means that it contains 1 mole of HCl per liter of solution.
- Therefore, the number of moles of HCl used in the reaction can be calculated as follows:

Moles of HCl = Concentration of HCl × Volume of HCl
= 1 × 0.150
= 0.150 moles

Step 2: Calculation of moles of NaOH used
- We know that the concentration of NaOH is 0.5 N, which means that it contains 0.5 moles of NaOH per liter of solution.
- Therefore, the number of moles of NaOH used in the reaction can be calculated as follows:

Moles of NaOH = Concentration of NaOH × Volume of NaOH
= 0.5 × 0.100
= 0.050 moles

Step 3: Calculation of moles of HCl used for M2CO3
- M2CO3 reacts with HCl to form 2 moles of HCl and 1 mole of M2CO3.
- Therefore, the number of moles of HCl used for M2CO3 can be calculated as follows:

Moles of HCl for M2CO3 = 0.150/2
= 0.075 moles

Step 4: Calculation of moles of M2CO3
- From Step 3, we know that 0.075 moles of HCl were used for 1 mole of M2CO3.
- Therefore, the number of moles of M2CO3 can be calculated as follows:

Moles of M2CO3 = 0.075/1
= 0.075 moles

Step 5: Calculation of Molecular Weight of M2CO3
- The molecular weight of M2CO3 can be calculated as follows:

Molecular weight of M2CO3 = (2 × Atomic weight of M) + Atomic weight of C + (3 × Atomic weight of O)
= (2 × Atomic weight of M) + 12.01 + (3 × 16.00)
= (2 × Atomic weight of M) + 60.03

Step 6: Calculation of Equivalent Weight of M
- The equivalent weight of M can be calculated as follows:

Equivalent weight of M = Molecular weight of M2CO3/Number of moles of M2CO3
= (2 × Atomic weight of M + 60.03)/0.075

Step 7: Final Answer
- Putting the values in the above equation, we get:

Equivalent weight of M = (2 × Atomic weight of M + 60.03)/0.075