A ball is rolled off along the edge of table with velocity 4 m/s. It h...
Explanation:
Given data:
- Initial velocity of the ball, u = 4 m/s
- Time taken to hit the ground, t = 0.4 s
- Acceleration due to gravity, g = 10 m/s²
Calculations:
- Using the equation of motion, s = ut + (1/2)at², where s is the distance fallen
- Substituting the values, we get s = 4(0.4) + (1/2)(10)(0.4)² = 1.6 m
- This is the horizontal distance covered by the ball before hitting the ground, which matches with option 'c'
- Now, using the formula for vertical distance fallen, h = (1/2)gt², where h is the height of the table
- Substituting the values, we get h = (1/2)(10)(0.4)² = 0.8 m
- This confirms that the height of the table is indeed 0.8 m, which matches with option 'a'
- The vertical velocity of the ball when it hits the ground can be calculated using the formula, v = u + gt
- Substituting the values, we get v = 4 + (10)(0.4) = 8 m/s
- Therefore, the ball hits the ground with a vertical velocity of 8 m/s, not 4 m/s as mentioned in option 'd'
- The angle at which the ball hits the ground with the vertical can be calculated using the formula, θ = tan⁻¹(v/u)
- Substituting the values, we get θ = tan⁻¹(8/4) = tan⁻¹(2) ≈ 63.43°
- Therefore, the angle at which the ball hits the ground is approximately 63.43°, not 60° as mentioned in option 'b'
Therefore, the incorrect statement is option 'b', as the ball hits the ground at an angle of approximately 63.43° with the vertical, not 60°.
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