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A particle of mass 5gm and charge 12×10^-9 travels a distance of 300cm across a potential difference of 500 volts. Find the acceleration.?
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A particle of mass 5gm and charge 12×10^-9 travels a distance of 300cm...
Calculation of acceleration of a particle across a potential difference of 500 volts
Given:
Mass of particle, m = 5 gm
Charge of particle, q = 12 × 10^-9
Distance travelled by particle, d = 300 cm
Potential difference, V = 500 volts
Formula:
The acceleration of a charged particle moving through a potential difference can be calculated using the formula:
a = (qV) / (md)
Calculation:
Substituting the given values in the formula:
a = (12 × 10^-9 × 500) / (5 × 10^-3)
a = 120 × 10^-6 / 5 × 10^-3
a = 24 m/s^2
Explanation:
When a charged particle moves through a potential difference, it gains kinetic energy. This energy can be converted into the particle's kinetic energy, which results in acceleration. The acceleration of a charged particle moving through a potential difference can be calculated using the formula, a = (qV) / (md), where q is the charge of the particle, V is the potential difference, m is the mass of the particle, and d is the distance travelled by the particle. In this problem, the values of q, V, m, and d are given, and we can substitute them in the formula to get the acceleration. The answer is 24 m/s^2.
Given:
Mass of particle, m = 5 gm
Charge of particle, q = 12 × 10^-9
Distance travelled by particle, d = 300 cm
Potential difference, V = 500 volts
Formula:
The acceleration of a charged particle moving through a potential difference can be calculated using the formula:
a = (qV) / (md)
Calculation:
Substituting the given values in the formula:
a = (12 × 10^-9 × 500) / (5 × 10^-3)
a = 120 × 10^-6 / 5 × 10^-3
a = 24 m/s^2
Explanation:
When a charged particle moves through a potential difference, it gains kinetic energy. This energy can be converted into the particle's kinetic energy, which results in acceleration. The acceleration of a charged particle moving through a potential difference can be calculated using the formula, a = (qV) / (md), where q is the charge of the particle, V is the potential difference, m is the mass of the particle, and d is the distance travelled by the particle. In this problem, the values of q, V, m, and d are given, and we can substitute them in the formula to get the acceleration. The answer is 24 m/s^2.
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A particle of mass 5gm and charge 12×10^-9 travels a distance of 300cm across a potential difference of 500 volts. Find the acceleration.?
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A particle of mass 5gm and charge 12×10^-9 travels a distance of 300cm across a potential difference of 500 volts. Find the acceleration.? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A particle of mass 5gm and charge 12×10^-9 travels a distance of 300cm across a potential difference of 500 volts. Find the acceleration.? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle of mass 5gm and charge 12×10^-9 travels a distance of 300cm across a potential difference of 500 volts. Find the acceleration.?.
A particle of mass 5gm and charge 12×10^-9 travels a distance of 300cm across a potential difference of 500 volts. Find the acceleration.? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A particle of mass 5gm and charge 12×10^-9 travels a distance of 300cm across a potential difference of 500 volts. Find the acceleration.? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle of mass 5gm and charge 12×10^-9 travels a distance of 300cm across a potential difference of 500 volts. Find the acceleration.?.
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