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What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6 m? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm ( Use π= 3.14 )?
Verified Answer
What length of tarpaulin 3 m wide will be required to make conical ten...
Given a conical tent with
Height ( h ) = 8m
Radius ( r ) = 6m
So, its length = l2 = h2 + r2
= l2 = ( 8 )2m + ( 6 )m2
= l2 = 64m + 36m
= l2 = 100m
= l = 10m
Curved surface area of the cone = TTrl
= 3.14 * 6m * 10m
= 188.4 cm2
The extra length of material that will be required for stiching margins and wastages in cutting is approx 20 cm = 0.2m
So, its length = l - 0.2m
and its width = 3m
area of sheet = CSA of tent
so the area of the trapaulln = l * b
= ( l - 0.2m ) * 3m = 188.4m^2
= l - 0.2m = 62.8m2
= l = 63m
Therefore, length of the trapaulin sheet required is 63m.
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Most Upvoted Answer
What length of tarpaulin 3 m wide will be required to make conical ten...
Given:
- Width of tarpaulin = 3 m
- Height of conical tent = 8 m
- Base radius of conical tent = 6 m
- Extra length required for stitching margins and wastage in cutting = 20 cm
Formula:
The slant height of a conical tent can be calculated using the Pythagorean theorem:
Slant height (l) = sqrt(r^2 + h^2)
The curved surface area of a conical tent can be calculated using the formula:
Curved surface area (CSA) = πrl
The length of tarpaulin required for making the conical tent can be calculated by adding the CSA to the extra length required for stitching margins and wastage.
Calculation:
1. Calculate the slant height (l) using the given height (h) and base radius (r):
l = sqrt(6^2 + 8^2)
l = sqrt(36 + 64)
l = sqrt(100)
l = 10 m
2. Calculate the curved surface area (CSA) of the conical tent using the slant height (l) and base radius (r):
CSA = πrl
CSA = 3.14 * 6 * 10
CSA = 188.4 m^2
3. Calculate the extra length required for stitching margins and wastage:
Extra length = 20 cm = 0.2 m
4. Calculate the total length of tarpaulin required:
Total length = CSA + Extra length
Total length = 188.4 + 0.2
Total length = 188.6 m
Answer:
The length of tarpaulin required to make the conical tent is 188.6 meters.
- Width of tarpaulin = 3 m
- Height of conical tent = 8 m
- Base radius of conical tent = 6 m
- Extra length required for stitching margins and wastage in cutting = 20 cm
Formula:
The slant height of a conical tent can be calculated using the Pythagorean theorem:
Slant height (l) = sqrt(r^2 + h^2)
The curved surface area of a conical tent can be calculated using the formula:
Curved surface area (CSA) = πrl
The length of tarpaulin required for making the conical tent can be calculated by adding the CSA to the extra length required for stitching margins and wastage.
Calculation:
1. Calculate the slant height (l) using the given height (h) and base radius (r):
l = sqrt(6^2 + 8^2)
l = sqrt(36 + 64)
l = sqrt(100)
l = 10 m
2. Calculate the curved surface area (CSA) of the conical tent using the slant height (l) and base radius (r):
CSA = πrl
CSA = 3.14 * 6 * 10
CSA = 188.4 m^2
3. Calculate the extra length required for stitching margins and wastage:
Extra length = 20 cm = 0.2 m
4. Calculate the total length of tarpaulin required:
Total length = CSA + Extra length
Total length = 188.4 + 0.2
Total length = 188.6 m
Answer:
The length of tarpaulin required to make the conical tent is 188.6 meters.
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What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6 m? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm ( Use π= 3.14 )?
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What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6 m? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm ( Use π= 3.14 )? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6 m? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm ( Use π= 3.14 )? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6 m? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm ( Use π= 3.14 )?.
What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6 m? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm ( Use π= 3.14 )? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6 m? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm ( Use π= 3.14 )? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6 m? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm ( Use π= 3.14 )?.
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