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If a car with acceleration dependent on displacement as a=6x^2 2x 5m/s^2 find the velocity of the particle ,when it is at x=3 metre ,given that ,initially it starts from x=1 with velocity 2m/s ?
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If a car with acceleration dependent on displacement as a=6x^2 2x 5m/s...
Problem Statement

A car has an acceleration function a=6x^2+2x+5m/s^2, where x is the displacement. If the car starts from x=1 with a velocity of 2m/s, what is its velocity when it reaches x=3m?


Solution


  1. Integrate the acceleration function to get the velocity function

  2. We can integrate the acceleration function to get the velocity function:

    v = ∫(6x^2+2x+5)dx = 2x^3 + x^2 + 5x + C

    where C is the constant of integration. To find C, we use the initial conditions:

    v(1) = 2m/s

    2 = 2(1)^3 + (1)^2 + 5(1) + C

    C = -5

    Therefore, the velocity function is:

    v = 2x^3 + x^2 + 5x - 5


  3. Find the velocity at x=3m

  4. To find the velocity when x=3m, we simply plug in x=3 into the velocity function:

    v(3) = 2(3)^3 + (3)^2 + 5(3) - 5 = 71m/s


  5. Answer

  6. The velocity of the car when it reaches x=3m is 71m/s.

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